The frequency of the wave will not change
Since this is a projectile motion problem, break down each of the five kinematic quantities into x and y components. To find the range, we need to identify the x component of the displacement of the ball.
Let's break them down into components.
X Y
v₁ 32 cos50 m/s 32 sin50 m/s
v₂ 32 cos50 m/s ?
Δd ? 0
Δt ? ?
a 0 -9.8 m/s²
Let's use the following equation of uniform motion for the Y components to solve for time, which we can then use for the X components to find the range.
Δdy = v₁yΔt + 0.5ay(Δt)²
0 = v₁yΔt + 0.5ay(Δt)²
0 = Δt(v₁ + 0.5ayΔt), Δt ≠ 0
0 = v₁ + 0.5ayΔt
0 = 32sin50m/s + 0.5(-9.8m/s²)Δt
0 = 2<u>4</u>.513 m/s - 4.9m/s²Δt
-2<u>4</u>.513m/s = -4.9m/s²Δt
-2<u>4</u>.513m/s ÷ 4.9m/s² = Δt
<u>5</u>.00s = Δt
Now lets put our known values into the same kinematic equation, but this time for the x components to solve for range.
Δdₓ = v₁ₓΔt + 0.5(a)(Δt)²
Δdₓ = 32cos50m/s(<u>5</u>.00s) + 0.5(0)(<u>5</u>.00)²
Δdₓ = 32cos50m/s(<u>5</u>.00s)
Δdₓ = 10<u>2</u>.846
Therefore, the answer is A, 102.9m. According to significant digit rules, neither would be correct, but 103m is the closest to 102.9m so I guess that is what it is.
What does "which" mean ? Does it mean to pick the right one out of a list that you're hiding from us ?
There's no way we can begin to make a choice if we don't know WHAT the samples are samples OF.
I CAN give you some info, however, that will probably help you make the right choice from the hidden list that you have.
If water is on the list, then that's the answer, EXCEPT if liquid ammonia is on the list. Liquid ammonia is the only known substance on Earth that beats water as the answer to this question.
If neither liquid ammonia NOR water is on your secret list of samples, then you're on your own, Bunky.
get this cleanser and a different one.
get some dirt.
get two clocks
put equal amounts od cleanser on the dirt and start both clocks
when one has workred stop its clock. same for other.
compare times
The magnitude of this vector:
18.4 mi-28.7 mj is 34.09m
Given:
vector is
18.4 mi-28.7 mj
Magnitude =
This magnitude of a vector formula summarizes the distinct vector measures along the x-axis, y-axis, and z-axis. It is represented by the symbol |v|. A vector's magnitude is either a positive number or zero, and it can never be negative. Let us finally understand the magnitude of a vector formula by considering a few solved cases.
A vector's magnitude is equal to its length. The magnitude of the vector an is indicated by the symbol a. For further information on vector magnitude, see the introduction to vectors.
This article deduces formulas for the magnitude of vectors in two and three dimensions in terms of their coordinates. The magnitude formula for a two-dimensional vector a=(a1,a2)
To learn more about motion of gravity from the given link:
brainly.com/question/14033610
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