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Juli2301 [7.4K]
2 years ago
15

What is the answer to this problem

Physics
1 answer:
vredina [299]2 years ago
6 0

420 m of total distance is covered by the skier on travelling from A to D.

Explanation:

As from the picture, it can be seen that first the skier moved from position A to position B. And the distance covered by this movement is 180 m. Then as the skier travels from position B to position C, the distance between these two positions is 140 m from the figure. As distance is a scalar quantity, the direction is not taken into consideration. So only the magnitudes of the distance between those points are added.

Now, the distance between A to B is 180 m and then from B to C is 140 m,  atlast from C to D, the distance is given as 100 m.

So, the total distance will be the sum of all the above found distances. Thus, the total distance will be 180+140+100 = 420 m.

As the question is about distance, so no need to write the direction for it.

Thus, the final answer will be 420 m of total distance is covered by the skier on travelling from A to D.

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If you put a total of 8.05×106×106 electrons on an intially electrically neutral wire of length 1.03 m, what is the magnitude of
olga_2 [115]

Answer:

The magnitude of the electric field is 0.1108 N/C

Explanation:

Given;

number of electrons, e = 8.05 x 10⁶

length of the wire, L = 1.03 m

distance of the field from the center of the wire, r = 0.201 m

Charge of the electron;

Q = (1.602 x 10⁻¹⁹ C/e) x (8.05 x 10⁶ e)

Q = 1.2896 x 10⁻¹² C

Linear charge density;

λ = Q / L

λ = (1.2896 x 10⁻¹² C) / (1.03 m)

λ = 1.252 x 10⁻¹² C/m

The magnitude of electric field at r = 0.201 m;

E = (\frac{1}{4 \pi \epsilon_o} )\frac{ 2 \lambda}{r} \\\\E = k \frac{ 2 \lambda}{r}\\\\E = (8.89*10^9)*\frac{2*1.252*10^{-12}}{0.201}  \\\\E = 0.1108 \ N/C

Therefore, the magnitude of the electric field is 0.1108 N/C

6 0
2 years ago
based on the law of conservation of energy. how can we reasonably improve a machines ability to do work? A.move the machine to a
natima [27]

The correct answer is

C. reduce the friction between its moving parts


In fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

8 0
3 years ago
Read 2 more answers
If the Earth absorbs more insolation from the sun than it radiates back, the Earth _____________.
professor190 [17]

Answer:

If the Earth absorbs more insolation from the sun than it radiates back, the Earth. warms

8 0
2 years ago
The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90
s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

6 0
3 years ago
A large lightning bolt consists of a 18.2~\text{kA}18.2 kA current that moved 30.0~\text{C}30.0 C of charge. Assuming a constant
marissa [1.9K]

Answer:

1.65\times {-3} \text { s}

Explanation:

Current is the rate of flow of charge.

I=\dfrac{Q}{t}

t = \dfrac{Q}{I}

t = \dfrac{30.0}{18.2\times10^3} =1.65\times {0-3} = 1.65\times {-3} \text { s}

6 0
2 years ago
Read 2 more answers
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