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Juli2301 [7.4K]
3 years ago
15

What is the answer to this problem

Physics
1 answer:
vredina [299]3 years ago
6 0

420 m of total distance is covered by the skier on travelling from A to D.

Explanation:

As from the picture, it can be seen that first the skier moved from position A to position B. And the distance covered by this movement is 180 m. Then as the skier travels from position B to position C, the distance between these two positions is 140 m from the figure. As distance is a scalar quantity, the direction is not taken into consideration. So only the magnitudes of the distance between those points are added.

Now, the distance between A to B is 180 m and then from B to C is 140 m,  atlast from C to D, the distance is given as 100 m.

So, the total distance will be the sum of all the above found distances. Thus, the total distance will be 180+140+100 = 420 m.

As the question is about distance, so no need to write the direction for it.

Thus, the final answer will be 420 m of total distance is covered by the skier on travelling from A to D.

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a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. the centrip
qaws [65]
Well, first of all, a car moving around a circular curve is not moving
with uniform velocity.  The direction of motion is part of velocity, and
the direction is constantly changing on a curve.

The centripetal force that keeps an object moving in a circle is

         Force  =  (mass of the object) · (speed)² / (radius of the circle)

         F  =  m s² / r

We want to know the radius, to rearrange the formula to give us
the radius as a function of everything else.

                                          F     =  m s² / r

Multiply each side by 'r':       F· r  =  m · s²

Divide each side by 'F':            r  =  m · s² / F    

We know all the numbers on the right side,
so we can pluggum in:

                      r  =       m       ·        s²      /     F

                      r  =  (1200 kg) · (20 m/s)² / (6000 N) .

I'm pretty sure you can finish it up from here.

                                      


5 0
3 years ago
what will be the restoring force if a spring with a spring constant of 45 newtons per meter is pulled 0.30 meters in the downwar
Anna35 [415]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the choices the can be found elsewhere:

A.) 14 newtons upward 
<span>B.) 45 newtons upward </span>
<span>C.) 67 newtons upward </span>
<span>D.) 130 newtons upward </span>
<span>E.) 150 newtons upward
</span>
The answer is A.) 14 newtons upward


7 0
3 years ago
A child bounces a 52 g superball on the sidewalk. The velocity change of the superball is from 20 m/s downward to 14 m/s upward.
marusya05 [52]

Answer:

Force on superball will be =9.8222\times 10^{-4}N

Explanation:

We have given mass of superball m = 52 gram = 0.052 kg

Velocity change from 20 m/sec downward to 14 m/sec upward

Let downward velocity is positive then upward velocity is negative

So downward velocity is + 20 m/sec and upward velocity is -14 m/sec

Time is given as 1800 sec

We know that acceleration is rate of change of velocity

So a=\frac{20-(-14)}{1800}=0.0188m/sec^2

According to newton second law

Force = ma = 0.052×0.0188 =9.8222\times 10^{-4}N

6 0
3 years ago
Read 2 more answers
A car is moving with an initial relocity of
MA_775_DIABLO [31]

Answer:

The final acceleration of the car, v = 70 m/s

Explanation:

Given,

The initial velocity of the car, u = 20 m/s

The acceleration of the car, a = 10 m/s²

The time period of travel, t = 5 s

Using the I equations of motion

                     v = u + at

                        = 20 + 10(5)

                        = 20 + 50

                        = 70 m/s

Hence, the final acceleration of the car, v = 70 m/s

4 0
3 years ago
if quasars often resemble little blue stars, what was it about them that so surprised astronomers when they were dis­covered?
Anna11 [10]

Quasar is famous for being an intergalactic object which is billions of years away from the earth yet can still be seen, unlike the other star body, unlike giant galaxies.

Hence, the fact that quasars can be detected from distances where even the biggest and most luminous galaxies cannot be seen means that "they must be intrinsically far more luminous than the brightest galaxies."

This condition, including other related evidence gotten in recent years concerning our galaxy, has shown that quasars are probably the central nuclei of very distant, very active galaxies.

The surprising thing was that quasars and active galaxies have a lot of mass in the center of the very small volume of the space.

Therefore, the surprising thing about quasars was that due to this mass and energy they are 100 times more luminous than Milky Way which means they have high recession velocity and a very large amount of red-shifting.

To learn more about quasars, refer: brainly.com/question/9965257

#SPJ4

8 0
1 year ago
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