They can tell what type/species the dinosaur was
Answer:
Here is an image attached with similar questions.
The correct answer is D where acceleration is function of time.
Explanation:
The force acting on the object is constant.
There is no change in the application of forces.
And we know that Force is the product of acceleration and masses.
Newtons second law: 
Regarding mass we know that it can neither be created nor destroyed.
So in
we have two constant terms, constant divided by constant will give the same result as 
There is no change in acceleration
with respect to time
.
So the most appropriate graph where time (t) is changing on
but acceleration doesn't changes is D.
The graph will be similar to
and will be horizontal to the
.
Option D depicts the same.
Answer:
Q = - 256 X 10⁻⁷ C .
Explanation:
Electric field due to a charge Q at a distance d from the center is given by the expression
E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹
Put the given value in the equation
9 x 10² = 
Q = 
Q = - 256 X 10⁻⁷ C .
It will be negative in nature as the field is directed towards the center.
As they grow up, they will separate with their mother and tend to their own self. They will learn to catch fish and stay alert for predators. Eventually, they will find their own mate and produce their own offspring.
This indicates nucleus of an atom constantly positively charged. an atom has an nuteral overall charge because it has the same amount of electrons as protons