Magnetism is an example of a property of what?

What is the molarity of a solution that contains 50.0g of NaOH (molar mass = 40 grams/mole) in 2.0L of solution?

Oksi-84 [34.3K]

It is 39.997 molarity

4 0

3 years ago

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How do most animals produce offspring

egoroff_w [7]

Answer:

Some animals produce offspring through asexual reproduction while other animals produce offspring through sexual reproduction. Both methods have advantages and disadvantages. Asexual reproduction produces offspring that are genetically identical to the parent because the offspring are all clones of the original parent.

Explanation:

6 0

3 years ago

Copper(II) sulfide, CuS, is used in the development of aniline black dye in textile printing. What is the maximum mass of CuS wh

Naya [18.7K]

Answer:

1.82 g is the maximum mass of CuS.

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $CuCl_2$ :

Molarity = 0.500 M

Volume = 38.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 38.0×10⁻³ L

Thus, moles of $CuCl_2$ :

$Moles=0.500 \times {38.0\times 10^{-3}}\ moles$

Moles of $CuCl_2$ = 0.019 moles

For $(NH_4)_2S$ :

Molarity = 0.600 M

Volume = 42.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 42.0×10⁻³ L

Thus, moles of $(NH_4)_2S$ :

$Moles=0.600 \times {42.0\times 10^{-3}}\ moles$

Moles of $(NH_4)_2S$ = 0.0252 moles

According to the given reaction:

$CuCl_2_{(aq)}+(NH_4)_2S_{(aq)}\rightarrow CuS_{(s)}+2NH_4Cl_{(aq)}$

1 mole of $CuCl_2$ reacts with 1 mole of $(NH_4)_2S$

So,

0.019 mole of $CuCl_2$ reacts with 0.019 mole of $(NH_4)_2S$

Moles of $(NH_4)_2S$ = 0.019 mole

Available moles of $(NH_4)_2S$ = 0.0252 mole

Limiting reagent is the one which is present in small amount. Thus, $CuCl_2$ is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of $CuCl_2$ gives 1 mole of $CuS$

0.019 mole of $CuCl_2$ gives 0.019 mole of $CuS$

Moles of $CuS$ formed = 0.019 moles

Molar mass of $CuS$ = 95.611 g/mol

Mass of $CuS$ = Moles × Molar mass = 0.019 × 95.611 g = 1.82 g

1.82 g is the maximum mass of CuS.

5 0

4 years ago

Help now!!!

kumpel [21]

The balanced chemical equation when sodium and oxygen react is as below

4 Na + O₂ → 2 Na₂O

Explanation

From equation above 4 moles of sodium (Na) react with 1 mole of oxygen (O₂) to produce sodium oxide ( Na₂O)

Since there is equal number number of atoms in side of reactants and in the side of product the equation is balanced.

For example there is 4 atoms of Na in side of reactant and 4 in side of product.

3 0

3 years ago

PLEASE ASSIST MEEEEEEE!!!!!!!!! 40 POINTS

lana66690 [7]

Answer:

Wavelength of this beam of light: $\rm 4.39\times 10^{-7}\; m$ .

Explanation:

The speed of light in vacuum is approximately $\rm 2.998\times 10^{8}\;m \cdot s^{-1}$ .

Light behaves like a wave. The wavelength of a wave is equal to the distance that it travels (in the given medium) in each period of oscillation.

On the other hand, the frequency of a wave is the number of periods in unit time. $1\rm \; Hz$ means one oscillation per second. The frequency of this particular wave is $\rm 6.83\times 10^{14}\; Hz$ . In other words, there are $6.83\times 10^{14}$ oscillations in each second.

The period of oscillation will be equal to

$\displaystyle t = \frac{1}{f} = \frac{1}{\rm 6.83\times 10^{14}\; s^{-1}}$ .

In that period of time, a beam of light in vacuum would have traveled

$\displaystyle \rm 2.998\times 10^{8}\; m\cdot s^{-1} \times \frac{1}{\rm 6.83\times 10^{14}\; s^{-1}} = 4.39\times 10^{-7}\; m$ .

In other words, if this beam of light of frequency $\rm 6.83\times 10^{14}\; Hz$ is in vacuum, its wavelength will be equal to $\rm 4.39\times 10^{-7}\; m$ .

8 0

3 years ago