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kipiarov [429]
3 years ago
15

Two plane mirrors are inclined at an angle of 70. For a ray of light, incident on mirror 1 , its angle of reflection from mirror

2 is
Physics
1 answer:
tester [92]3 years ago
8 0

Answer:

D

Explanation:

Two plane mirrors are inclined at 70∘. A ray incident on one mirror at incidence angle θ after reflection falls on the second mirror and is reflected from there parallel to the first mirror, The value of θ is. ∴(θ)=50∘.

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A soccer ball is kicked from the top of one building with a height of H1 = 30.2 m to another building with a height of H2 = 12.0
viktelen [127]

Hi there!

Initially, we have gravitational potential energy and kinetic energy. If we set the zero-line at H2 (12.0m), then the ball at the second building only has kinetic energy.

We also know there was work done on the ball by air resistance that decreased the ball's total energy.

Let's do a summation using the equations:
KE = \frac{1}{2}mv^2 \\\\PE = mgh

Our initial energy consists of both kinetic and potential energy (relative to the final height of the ball)

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E_f = \frac{1}{2}mv_f^2

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The work done by air resistance is equal to the difference between the initial energy and the final energy of the soccer ball.

Therefore:
W_A = \frac{1}{2}mv_i^2 + mg(H_1 - H_2) -  \frac{1}{2}mv_f^2

Solving for the work done by air resistance:
W_A = \frac{1}{2}(.450)(15.1^2)+ (.450)(9.8)(30.2 - 12) -  \frac{1}{2}(.450)(19.89^2)

W_A = \boxed{42.552 J}

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2 years ago
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Answer:

15v

Explanation:

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= 0.3*50

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I HOPE IT'S HELPFUL

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V125BC [204]
<span>Basically, the variable n is equal to the amount of P out of the system divided by the about of P into the system

</span>
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2 years ago
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