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3 years ago

15

Two plane mirrors are inclined at an angle of 70. For a ray of light, incident on mirror 1 , its angle of reflection from mirror

2 is

1 answer:

tester [92]3 years ago

8 0

Answer:

D

Explanation:

Two plane mirrors are inclined at 70∘. A ray incident on one mirror at incidence angle θ after reflection falls on the second mirror and is reflected from there parallel to the first mirror, The value of θ is. ∴(θ)=50∘.

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HELP ME !!!Question 4 of 10

Dmitrij [34]

Answer:

The answers are C and D

Explanation:

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3 years ago

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The relative density of oak wood is 0.64 .find the density in the cgs system

Zepler [3.9K]

Relative density is defined as:
dr = ds / dw
where:
dr: relative density
ds: density of the substance.
dw: density of water.
In this case we have the relative density of oak wood:
dr = 0.64.
We want to find the density of the substance: ds
Therefore we need to know the density of water in the cgs unit system:
dw = 1g / c ^ 3
Finally:
ds = dr * dw
ds = 0.64 * 1 g / cm ^ 3
ds = 0.64 g / c ^ 3
The density of the oak wood in cgs is 0.64 g / cm ^ 3

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3 years ago

An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a

devlian [24]

Answer:

a

$D = 1162.7 \ m$

b

$\beta =- 65.55^o$

Explanation:

From the question we are told that

The speed of the airplane is $u = 92.3 \ m/s$

The angle is $\theta = 51.1^o$

The altitude of the plane is $d = 532 \ m$

Generally the y-component of the airplanes velocity is

$u_y = v * sin (\theta )$

=> $u_y = 92.3 * sin ( 51.1 )$

=> $u_y = 71.83 \ m/s$

Generally the displacement traveled by the package in the vertical direction is

$d = (u_y)t + \frac{1}{2}(-g)t^2$

=> $-532 = 71.83 t + \frac{1}{2}(-9.8)t^2$

Here the negative sign for the distance show that the direction is along the negative y-axis

=> $4.9t^2 - 71.83t - 532 = 0$

Solving this using quadratic formula we obtain that

$t = 20.06 \ s$

Generally the x-component of the velocity is

$u_x = u * cos (\theta)$

=> $u_x = 92.3 * cos (51.1)$

=> $u_x = 57.96 \ m/s$

Generally the distance travel in the horizontal direction is

$D = u_x * t$

=> $D = 57.96 * 20.06$

=> $D = 1162.7 \ m$

Generally the angle of the velocity vector relative to the ground is mathematically represented as

$\beta = tan ^{-1}[\frac{v_y}{v_x } ]$

Here $v_y$ is the final velocity of the package along the vertical axis and this is mathematically represented as

$v_y = u_y - gt$

=> $v_y = 71.83 - 9.8 * 20.06$

=> $v_y = -130.05 \ m/s$

and v_x is the final velocity of the package which is equivalent to the initial velocity $u_x$

So

$\beta = tan ^{-1}[-130.05}{57.96 } ]$

$\beta =- 65.55^o$

The negative direction show that it is moving towards the south east direction

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3 years ago

Ajdaifsgodtistizhxtsgoachoach

Norma-Jean [14]

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3 years ago

O D. Both objects won't move at all. They will just stay where they were released.

astraxan [27]

Answer:

Do not see a picture or graph but suspect it would show the golf ball falling faster and striking the ground slightly before the soccer ball.

Probably D: Soccer ball was affected by air resistance more than the golf ball.

Explanation:

Even though heavier, friction loss of the greater surface area soccer ball will counter pull of gravity more than the compact golf ball.

In a vacuum, (no friction) both objects fall at the same rate regardless of mass.

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3 years ago