Answer:
Explanation:
Given
Sphere of Radius R
Suppose mass of block is m
At any instant \theta Normal reaction(N) and weight(mg) is acting such that
, where v is velocity of block at any angle \theta
When block is just about to leave then N=0
therefore

-------------------1
Also by conserving Energy we get
Potential Energy=kinetic Energy of block

here h=vertical distance traveled by block
From diagram



-----------------2
From 1 and 2



Thus from this value of h is



Answer:
Right shoe
Explanation:
Let the mass and velocity of incoming puck be m and v respectively.
Momentum of the colliding puck will be mv
In case of first case , the momentum of puck becomes zero so change in momentum after collision with left shoe
= mv - 0 = mv
If time duration of collision be t
rate of change of momentum
= mv / t
This is the force exerted by puck on the left shoe .
Now let us consider collision with right shoe
momentum after collision with right shoe
- mv
change in momentum
= mv - ( - mv ) = 2mv
If time duration of collision be t
rate of change of momentum
= 2mv / t
This is the force exerted by puck on the right shoe .
Since the force on the right shoe is more , this shoe will have greater speed
after collision.
Answer:
The options are:
Test 1: Mix a teaspoon of sodium bicarbonate into a cup of warm water to see if it dissolves.
Test 2: Mix a teaspoon of sodium bicarbonate into a cup of vinegar to see if it fizzes.
Test 3: Heat a teaspoon of sodium bicarbonate in the oven to see if its melting point is less than 400 degrees Fahrenheit.
Which statement provides the best assessment of his tests?
The answer is Test 2: Mix a teaspoon of sodium bicarbonate into a cup of vinegar to see if it fizzes.
This is because it will indicate the chemical property of the sodium bicarbonate as a result of its reaction with another chemical compound, a vinegar.
Tests 1 and 3 will show a physical property of the substance as a result of the physical characteristics such as solubility and melting point .