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Firdavs [7]
3 years ago
10

What is the IUPAC name Of CH3-CH2-CH2-CH=O I COOH

Chemistry
2 answers:
Blizzard [7]3 years ago
8 0

Answer:

Explanation:

It is Butanoic Acid

prisoha [69]3 years ago
6 0
The answer is butanoic acid
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Which skill involves creating representations of complex objects or processes? A. classifying B. predicting C. making models D.
Murljashka [212]

Answer:

C. making models

Explanation:

Making models facilitates constructing depictions of complex objects or practices that enable students to practice and understand how things work which can not be observed and measured directly. Model making needs abstract thinking about the tools and material used, spatial thinking, and well-organized idea of the project to create complex objects.

8 0
3 years ago
What elements is mercuric oxide composed of?
Tomtit [17]

Answer:

Lavoisier reacted mercury with oxygen to form mercuric oxide

5 0
3 years ago
Read 2 more answers
A pond has the dimensions of 25 meters long by 20 meters wide. If there are 100 frogs living in the pond, what is the "populatio
sweet-ann [11.9K]

Answer:

D. 5 frogs/sq meter

Explanation:

5 0
3 years ago
A 25.0 mL sample of 0.25 M potassium carbonate (K2CO3) solution is added to 30.0 mL of a 0.40 M barium nitrate (Ba(NO3)2) soluti
ozzi

Answer:

0.10M of Ba²⁺ is the concentration of the metal in excess

Explanation:

Based on the chemical reaction:

K₂CO₃(aq) + Ba(NO₃)₂(aq) → BaCO₃(s) + 2KNO₃(aq)

<em>1 mole of potassium carbonate reacts per mole of barium nitrate</em>

<em />

To solve this question we need to find the moles of each salt to find then the moles of Barium in excess:

<em>Moles K₂CO₃:</em>

0.025L * (0.25mol / L) = 0.00625moles K₂CO₃ = moles CO₃²⁻

<em>Moles Ba(NO₃)₂:</em>

0.030L * (0.40mol/L) = 0.012 moles of Ba(NO₃)₂ = 0.012 moles of Ba²⁺

That means moles of Ba²⁺ that don't react are:

0.012 mol - 0.00625mol = 0.00575 moles Ba²⁺

In 25 + 30mL = 55mL:

0.00575 moles Ba²⁺ / 0.055L =

<h3>0.10M of Ba²⁺ is the concentration of the metal in excess</h3>
4 0
3 years ago
Calculate the amount of heat lost by 23 g of water when its temperature drops from 68.0°C to 31.0°C. The specific heat of water
34kurt

Answer:

3557J is the heat lost by the water

Explanation:

Using the equation:

Q = m*C*ΔT

<em>Where Q is change in heat</em>

<em>m is mass of substance (23g of water)</em>

<em>C is specific heat of the substance (4.18J/g°C)</em>

<em>And ΔT is change in temperature (68.0°C - 31.0°C = 37.0°C)</em>

<em />

we can find the amount of heat lost as follows:

Q = 23g*4.18J/g°C*37°C

Q =

3557J is the heat lost by the water

<em />

8 0
3 years ago
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