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3 years ago

It's important to do cardiovascular exercise on a regular basis because it _____.

Physics

1 answer:

n200080 [17]3 years ago

4 0

Answer:

I believe it improves your hearts stroke volume

If im wrong plz let me know

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If Earth was with no tilt, would we still have seasons at all? If so, how would they be different?

murzikaleks [220]

Answer:

If earth had no tilt, we would have no seasons.

Explanation:

As stated in the answer, if the earth had no tilt we wouldn't have seasons. The earth all around the globe would maintain the same temperature,

And due to the no tilt it would also change our orbit to a bit larger slant, in January when we are at our closest to the sun we WOULD have a mini summer. For the North and South Pole, they would remain cold.

8 0

4 years ago

A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 24 N. Starting from rest, the sle

Gnoma [55]

Answer:

The coefficient friction

μ = 0.11

Explanation:

To find the coefficient of kinetic can be find using conserved energy equations and knowing the friction force is

fk = μ * N

Now to determine use the equation

Wf = ¹/₂ * m * v² = ¹/₂ * 17 kg * 2.5² m / s = 53.125 J

We = 24.0 N * cos (0) * 9.4 m = 225.6 J

Wt = Wf - We = 53.125 J - 225.6 J = - 172.475 J

Wt = fk * d

fk = Wt / d = 18.35 N

Now to find the coefficient μ'

N = m * g = 17 kg * 9.8 m/s² = 166.6 N

μ = fk / N

μ = 18.35 N / 166.6 N

μ = 0.11

4 0

3 years ago

HELPPP MEEE PLEASSSE ASAP IT WOULD MEAN ALOT

777dan777 [17]

C. Lenses form images byvrefracting light; mirrors do not

8 0

3 years ago

Two timpani (tunable drums) are played at the same time. One is correctly tuned so that when it is struck, sound is produced tha

yKpoI14uk [10]

Answer:

Explanation:

Given

Wavelength of first timpani $\lambda _1=2.2\ m$

Frequency corresponding to this Wavelength

$f_1=\frac{v}{\lambda _1}$

where $v=velocity\ of\ sound (343 m/s)$

$f_1=\frac{343}{2.2}$

$f_1=155.9\ Hz$

Wavelength of Second timpani $\lambda _2=2.1\ m$

Frequency corresponding to this Wavelength

$f_2=\frac{v}{\lambda _2}$

$f_2=\frac{343}{2.1}=163.33\ Hz$

Beat frequency $=f_2-f_1$

Beat frequency $=163.33-155.9=7.43$

so approximately 7 beats per second

4 0

4 years ago

The pressure in a section of horizontal pipe with a diameter of 2.5 cm is 139 kPa. Water ï¬ows through the pipe at 2.9 L/s. If t

My name is Ann [436]

Answer:

d = 2*0.87 = 1.75 cm

Explanation:

by using flow rate equation to determine the speed in larger pipe

$\phi =\pi r^2 v$

$v = \frac{\phi}{\pi r^2}$

$= \frac{2900 cm^3/s}{3.14(1.25cm)^2}$

= 591.10 cm/s

= 5.91 m/s

by Bernoulli's EQUATION

$p1 +\frac{1}{2} \rho v1^2 = p2 +\frac{1}{2} \rho v2^2$

$139000+ \frac{1}{2}*1000*5.91^2 = 101000 +\frac{1}{2}*1000* v2^2$

solving for v2

v2 = 10.53 m/s

diameter can be determine by using flow rate equation

$q = v \pi r^2$

$r^2 = \frac{q}{\pi v}$

$= \frac{2900}{3.14*1053}$

r = 0.87 cm

d = 2*0.87 = 1.75 cm

5 0

3 years ago