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IRISSAK [1]
3 years ago
13

PLEASE HELPPPPPPP!!!!!!!!!!

Physics
1 answer:
natka813 [3]3 years ago
8 0

Answer:

F' = 800 N

Explanation:

The electrical force between charges is 400 N.

The electrical force between two charges is given by :

F=k\dfrac{q_1q_2}{r^2}

If q₁' = 2q₁, new force becomes,

F'=k\dfrac{q_1'q_2'}{r^2}\\\\F'=k\dfrac{2q_1\times q_2}{r^2}\\\\F'=2\times F\\\\F'=2\times 400\\\\F'=800\ N

So, the new force becomes 800 N.

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Answer:

Same direction to produce maximum magnitude and opposite direction to produce minimum magnitude

Explanation:

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Also let A and B be the magnitude of vector A and B, respectively.

We have the parallel component after addition be

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= \sqrt{A^2(cos^2a + sin^2a) + B^2 + 2ABcos(a)}

= \sqrt{A^2 + B^2 + 2ABcos(a)}

As A and B are fixed, the equation above is maximum when cos(a) = 1, meaning a = 0 degree and vector A and B are in the same direction, and minimum with cos(a) = -1, meaning a = 180 degree and vector A and B are in opposite direction.

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What do radio waves carry
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g A spherical container of inner diameter 0.9 meters contains nuclear waste that generates heat at the rate of 872 W/m3. Estimat
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Hence, the rate of heat transfer is as follows.

Q = q \times V

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Substitute the values into above formula as follows.

Q = q \times \frac{4}{3} \pi r^{3}\\= 872 W/m^{3} \times \frac{4}{3} \times 3.14 \times (0.45 m)^{3}\\= 332.67 W

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A car moving at 10 m/s crashes into a large bush and stops in 1.3 m. Using the Work-Energy theorem, calculate the average force
ad-work [718]

Answer:

The magnitude of the average force the seat belt exerts on the passenger is 2692.3 N.

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Explanation:

Hi there!

The negative work (W) needed to bring a moving object to stop is equal to its kinetic energy (KE):

W = KE

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Where:

F = applied force on the passenger.

s = displacement of the passenger.

m = mass of the passenger.

v = velocity of the passenger.

Solving the equation for F:

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Replacing with the data:

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According to the second law of Newton:

F = m · a

Where "a" is the acceleration of the passenger.

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v = velocity of the passenger at time t.

v0 = initial velocity.

t = time.

a = acceleration.

When the passenger stops, its velocity is zero. So replacing a = F/m, let´s solve the equation for the time it takes the passenger to stop:

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t =0.26 s

It takes 0.26 s to bring the passenger in the car to a halt.

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