(a) The time for the capacitor to loose half its charge is 2.2 ms.
(b) The time for the capacitor to loose half its energy is 1.59 ms.
<h3>
Time taken to loose half of its charge</h3>
q(t) = q₀e-^(t/RC)
q(t)/q₀ = e-^(t/RC)
0.5q₀/q₀ = e-^(t/RC)
0.5 = e-^(t/RC)
1/2 = e-^(t/RC)
t/RC = ln(2)
t = RC x ln(2)
t = (12 x 10⁻⁶ x 265) x ln(2)
t = 2.2 x 10⁻³ s
t = 2.2 ms
<h3>
Time taken to loose half of its stored energy</h3>
U(t) = Ue-^(t/RC)
U = ¹/₂Q²/C
(Ue-^(t/RC))²/2C = Q₀²/2Ce
e^(2t/RC) = e
2t/RC = 1
t = RC/2
t = (265 x 12 x 10⁻⁶)/2
t = 1.59 x 10⁻³ s
t = 1.59 ms
Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.
Learn more about energy stored in capacitor here: brainly.com/question/14811408
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Answer:
The magnetic flux through a loop is zero when the B field is perpendicular to the plane of the loop.
Explanation:
Magnetic flux are also known as the magnetic line of force surrounding a bar magnetic in a magnetic field.
It is expressed mathematically as
Φ = B A cos(θ) where
Φ is the magnetic flux
B is the magnetic field strength
A is the area
θ is the angle that the magnetic field make with the plane of the loop
If B is acting perpendicular to the plane of the loop, this means that θ = 90°
Magnetic flux Φ = BA cos90°
Since cos90° = 0
Φ = BA ×0
Φ = 0
This shows that the magnetic flux is zero when the magnetic field strength B is perpendicular to the plane of the loop.
Answer:
539.5°
Explanation:
33.3 revolutions per minute
1 revolution = 360°
1 minute = 60 seconds
hence
33.3 revs ----> 1 minute = 60 seconds
X revs -----------> 2.70 seconds
X = (33.3 x 2.7)÷60 = 1.4985 revolutions in 2.70 seconds
1.4985 revolutions = 1.4985 x 360 = 539.46
which is approximately 539.5°
<u>Ques</u><u>tion</u><u>:</u>
Azaria's pet lizard runs a distance of 45 meters in 24 seconds. What is the speed of the lizard?
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<u>Solu</u><u>tion</u><u>:</u>
We are given,
- Distance = d = 45 m
- Time = t = 24 s
Speed is given by:
Putting the given values,
s = (45 m)/(24 s)
=> s = 1.875 m/s
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