Answer:
Here's what I get
Explanation:
1. Balanced equation
HQ⁻ + CH₃-Br ⟶ HQ-CH₃ + Br⁻
(I must use HQ because the Brainly Editor thinks the O makes a forbidden word)
2. Mechanism
HQ⁻ + CH₃-Br ⟶[HQ···CH₃···Br]⁻⟶ HQ-CH₃ + Br⁻
A C B
The hydroxide ion attacks the back side of the carbon atom in the bromomethane (A).
At the same time as the Q-H bond starts to form, the C-Br bond starts to break.
At the half-way point, we have a high-energy intermediate (C) with partially formed C-O and C-Br bonds.
As the reaction proceeds further, the Br atom drops off to form the products — methanol and bromide ion (B).
3. Energy diagram
See the diagram below.
Answer:
13598 J
Explanation:
Q = m × c × ∆T
Where;
Q = amount of energy (J)
m = mass (grams)
c = specific heat capacity
∆T = change in temperature
m = 65g, specific heat capacity of water = 4.184J/g°C, initial temperature= 100°C, final temperature = 150°C
Q = 65 × 4.184 × (150 - 100)
Q = 271.96 × 50
Q = 13598 J
Hence, 13598 J of energy is required to boil 65 grams of 100°C water and then heat the steam to 150°C.
Volume of carbon dioxide absorbed = 33.6 L ≈ 34 L
Explanation:
We have the following chemical reaction:
CO₂ (g) + 2 LiOH (s) → Li₂CO₃ (s) + H₂O (l)
Now we devise the following reasoning:
if 1 mole of carbon dioxide reacts with 2 moles of lithium hydroxide
then X moles of carbon dioxide reacts with 3 moles of lithium hydroxide
X = (1 × 3) / 2 = 3/2 moles of carbon dioxide
And we calculate the volume of carbon dioxide using the following formula:
number of moles = volume / 22.4
volume = number of moles × 22.4
note: units for 22.4 are "L / mole"
volume of carbon dioxide = (3/2) × 22.4 = 33.6 L ≈ 34 L
Learn more about the reaction of carbon dioxide with metal hydroxides:
brainly.com/question/6979534
brainly.com/question/4316721
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Gravity, running water (rivers, etc.), wind, waves,and glaciers.
H2 is known to exist. For dihydrogen, H2, we can identify the frontier molecular orbitals (FMOs). The highest occupied molecular orbital (or HOMO) is the σ (sigma) 1s MO. The lowest unoccupied MO (LUMO) is the σ* (sigma star) 1s MO which is antibonding.