Answer:
#Selling vehicles
import locale
locale.setlocale( locale.LC_ALL, 'en_CA.UTF-8' )
#Declaration of variables
total_pay=0
total_sales=0
#Selling details
for i in range(0,2):
#Ask the type of sell
type=input("Enter the type of the car you sold(used/new)? ")
#Check error
while(type.upper()!="USED" and type.upper()!="NEW"):
print('ERROR!!!Should be used or new!!Please Re-enter')
type=input("Enter the type of the car you sold(used/new)? ")
#Input price of the car
price=float(input("Enter the price of the car: "))
#Calculations
if(type.upper()=="NEW"):
total_pay+=1500
else:
total_pay+=price*.05
total_sales+=price
#Display results
print('Total Pay of the sale person = ',locale.currency(total_pay))
print('Total Sales = ',locale.currency(total_sales))
Answer:
r=0.31
Ф=18.03°
Explanation:
Given that
Diameter of bar before cutting = 75 mm
Diameter of bar after cutting = 73 mm
Mean diameter of bar d= (75+73)/2=74 mm
Mean length of uncut chip = πd
Mean length of uncut chip = π x 74 =232.45 mm
So cutting ratio r
r=0.31
So the cutting ratio is 0.31.
As we know that shear angle given as
Now by putting the values
\
Ф=18.03°
So the shear angle is 18.03°.
The answer is the second one b
Answer:
Answered below.
Explanation:
A) Both spheroidite & tempered martensite possess sphere - like cementite particles within their microstructure known as a ferrite matrix. However, the difference is that these particles are much larger for spheroidite than tempered.
B) Tempered martensite is much harder and stronger than spheroidite primarily because there is much more ferrite - cementite phase boundary area for its sphere - like cementite particles.
This is because the greater the boundary area, the more the hardness.
Answer: 0.025 in = 0.065 mm
Explanation: To convert the value in inches to mm we have to multiply the inches by the conversion factor 25.4.
So, 0.025 × 25.4 = 0.065 mm (millimeter)
Conversion formula for calculation in (inch) into mm is:
Value in mm = Value in in × 25.4
- One inch is equal to the 25.4 mm.
