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sergejj [24]
3 years ago
10

Help please! 1. L 2. M 3. X 4. Z

Chemistry
1 answer:
Mkey [24]3 years ago
5 0
1. L
Number one because the lines match up
You might be interested in
Problem PageQuestion A chemistry student needs 10.0g of dimethyl sulfoxide for an experiment. By consulting the CRC Handbook of
PIT_PIT [208]

Answer:

9.09cm3

Explanation:

The following data were obtained from the question:

Mass of dimethyl sulfoxide = 10g

Density of dimethyl sulfoxide = 1.10gcm−3

Volume of dimethyl sulfoxide =?

The density of a substance is simply the mass substance per unit volume of the substance. It is represented mathematically as:

Density = Mass/volume.

With the above formula, we can obtain the volume of dimethyl sulfoxide as follow:

Density = Mass/volume

1.10gcm−3 = 10g/ volume

Cross multiply to express in linear form

1.10gcm−3 x Volume = 10g

Divide both side by 1.10gcm−3

Volume = 10g / 1.10gcm−3

Volume = 9.09cm3

Therefore, the volume of dimethyl sulfoxide the student should pour out is 9.09cm3

7 0
3 years ago
A piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The graduated cylinde
Mademuasel [1]

The density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

<h3>How to calculate density?</h3>

The density of a substance can be calculated by dividing the mass of the substance by its volume. That is;

Density = mass ÷ volume

According to this question, a piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The density can be calculated as follows:

Density = 17.1g ÷ 17.00mL

Density = 1.005g/mL

Therefore, the density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.

Learn more about density at: brainly.com/question/15164682

#SPJ1

6 0
1 year ago
Can you give me more explanation in the picture?
PolarNik [594]
Read the paper more carefully if you don't understand it
5 0
3 years ago
A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio
MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass  / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758  grams

Thus, the percent yield for this reaction = \frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100

or

the percent yield for this reaction = \frac{0.53}{0.5758}\times100

or

the percent yield for this reaction = 92.04%

6 0
3 years ago
pleeeaaaseeeee answer asappppppppp!!!!!!!!!!! Explain the processes of evaporation and condensation using the image above
goldfiish [28.3K]
In the lake that the rivers lead, water molecules evaporate into the sky and form clouds. In the sky, these water droplets condense and form clouds that will eventually rain.
5 0
3 years ago
Read 2 more answers
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