According to Henry's law, solubility of solution is directly proportional to partial pressure thus,

Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.
Putting the values in equation:

On rearranging,

Therefore, solubility will be 1.88 mg of
gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.
Answer:
Explanation:
Moles of
= 1 mole
Moles of
= 1 mole
Volume of solution = 1 L
Initial concentration of
= 1 M
Initial concentration of
= 1 M
The given balanced equilibrium reaction is,

Initial conc. 1 M 0M 1 M
At eqm. conc. (1-2x) M (2x) M (1+x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[NO]^2[Cl_2]}{[NOCl]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%5BCl_2%5D%7D%7B%5BNOCl%5D%5E2%7D)
The
= 
Now put all the given values in this expression, we get :

By solving the term 'x', we get :

Concentration of
at equilibrium= (2x) M =
Its a C with 4 dots, 1 on top,1 on bottom, 1 on the left and 1 on the right
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.