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3 years ago

It's real easy but I don't know how to explain stuff ...

Physics

1 answer:

mixas84 [53]3 years ago

8 0

Answer:

Explanation:

From <em>https://epgna.com/stop-condensation-shipping-container</em>

"[C]ontainer condensation occurs when the walls of a container become cooler than the dew point of the air found inside the container... Once this occurs, the moisture falls out of vapor into liquid form, which then builds and collects on the walls and roof"

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^^ help :c

ipn [44]

I need help to I have a test and I need help to

6 0

3 years ago

If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot

Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=I_{1}+I_{2}$

$I=(m+m_{1})\times r^2+(m+m_{2})\times r^2$

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

$I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2$

$I=117.45\ kg-m^2$

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

8 0

4 years ago

Suppose you have a coffee mug with a circular cross section and vertical sides (uniform radius). What is its inside radius if it

Oksanka [162]

Coffee mug is cylindrical shape. Therefore,
Volume of mug = volume of cylinder = πr²h

r = inner radius of mug. h = height of coffee = 6 cm.
Density of coffee = Density of water = 1 g/ml

Therefore, volume of coffee = mass/density = 400/1 = 400 ml = 400 cm³
Volume of coffee = πr²h
400= πr²(6)
r² = 21.23
r = inner radius of mug = 4.607 cm

6 0

4 years ago

A ball dropped from a bridge takes 3.0 seconds to reach the water below. How far is the bridge from the water?

Komok [63]

Since it is dropped, initial velocity u = 0

Using s = ut + (1/2)gt^2, putting u = 0, g = 10 m/s^2

s =(1/2)gt^2, t = 3s

s = 0.5 * 10 * 3 *3

s = 45 m.

The bridge is 45m above the water.

8 0

3 years ago

How to find initial velocity, when the acceleration is slowing down.

Makovka662 [10]

Example: Vi= Vf-(at) , Vf=200m/s , a = 10m/s2 , t = 12s

8 0

3 years ago