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8_murik_8 [283]
2 years ago
6

A ball dropped from a bridge takes 3.0 seconds to reach the water below. How far is the bridge from the water?

Physics
1 answer:
Komok [63]2 years ago
8 0
Since it is dropped, initial velocity u = 0

Using s = ut + (1/2)gt^2,        putting u = 0,  g = 10 m/s^2

s =(1/2)gt^2,                  t = 3s

s = 0.5 * 10 * 3 *3

s = 45 m.

The bridge is 45m above the water.
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When you push a child on a swing, you are doing work on the child because _____.
max2010maxim [7]

ur answer is A or also known as

When you push a child on a swing, you are doing work on the child because  you are pushing against the force of gravity

hope this helps :)

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3 years ago
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Convection currents produce the heat in the Earth’s interior.
DaniilM [7]

Answer:

False

Explanation:

Convection currents do not produce heat. In fact, convection current are a method of transfer of heat, not of production. Convection occurs when there is a fluid which is heated from bottom, from an external source of heat (such as a pot of boiling water over a flame): the bottom part of the fluid becomes warmer, and so less dense than the colder part, therefore it starts moving up, and it is replaced by the colder parts of the fluid, which go down. Later, these colder parts become warmer, so they start going up, being replaced by new colder parts, etc... in a cycle. This is known as convection current, but it requires an external source of heat, it does not produce heat by itself.

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3 years ago
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A body is accelerated continuously. What is the form of the graph
Andrej [43]

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If a body is constantly accelerating the graph would be one-quadrant

4 0
3 years ago
A 0.0780 kg lemming runs off a
kotegsom [21]

Answer:

5.01 J

Explanation:

Info given:

mass (m) = 0.0780kg

height (h) = 5.36m

velocity (v) = 4.84 m/s

gravity (g) = 9.81m/s^2

1. First, solve for Kinetic energy (KE)

KE = 1/2mv^2

1/2(0.0780kg)(4.84m/s)^2 = 0.91 J

so KE = 0.91 J

2. Next, solve for Potential energy (PE)

PE = mgh

(0.0780kg)(9.81m/s^2)(5.36m) = 4.10 J

so PE = 4.10 J

3. Mechanical Energy , E = KE + PE

Plug in values for KE and PE

KE + PE = 0.91J + 4.10 J = 5.01 J

4 0
2 years ago
Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
salantis [7]

Explanation:

Mass of bumper cars, m_1=m_2=110\ kg

Initial speed of car A, u_1=8\ m/s

Initial speed of car Z, u_2=-10\ m/s

Final speed of car A after the collision, v_1=-10\ m/s

We need to find the velocity of car Z after the collision. Let it is equal to v_2. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

110\times 8+110\times (-10)=110\times (-10)+110v_2

v_2=\dfrac{-1320}{110}\ m/s

v_2=-12\ m/s

So, the velocity of car Z after the collision is (-12 m/s). Hence, this is the required solution.

5 0
3 years ago
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