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siniylev [52]
3 years ago
15

A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approxi

mate acceleration of the car?
Physics
2 answers:
densk [106]3 years ago
4 0

Answer : The approximate acceleration of the car is, 6.008m/s^2

Solution : Given,

Initial velocity of the car = 0 m/s

Distance covered = 120 meter

Time taken = 6.32 second

Using second law of motion,

s=ut+\frac{1}{2}at^2

where,

s = distance covered

u = initial velocity

t = time taken

a = acceleration

Now put all the given values in the above equation, we get

(120m)=(0m/s)\times (6.32s)+\frac{1}{2}\times a\times (6.32s)^2

a=6.008m/s^2

Therefore, the approximate acceleration of the car is, 6.008m/s^2

Verizon [17]3 years ago
3 0
Using kinematic equation s=ut + 1/2 at^2(u = initial velocity=0, s=120m, t= 6.32s), 120 = 0(t) + 1/2 a(6.32)^2. a = 120x2/(6.32)^2 = 6m/s^2.  
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3 years ago
A child drops a ball from a window. The ball strikes the ground in 3.0 seconds. What is the velocity of the ball the instant bef
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29.396988 m/s

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An approximate answer is found from an equation from constant acceleration kinematics:

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v = 29.397259 m/s

Now, the above method is an approximation that makes the technically incorrect assumption that the acceleration of gravity is a constant throughout the entire fall. You get away with it because the drop is very short. In another situation, it might not be. So it would be nice to develop a more accurate method that does not assume constant gravitational acceleration. For that, we begin with the Vis Viva equation:

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Using an iterative method (e.g. Newton's or Danby's), we can determine that the altitude,

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5 0
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