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azamat
3 years ago
14

Anyone else ever done this? Please help !!

Chemistry
1 answer:
Oksanka [162]3 years ago
5 0

Answers for criss-cross (except Q3) is in the above picture.

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Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).​
ser-zykov [4K]

Answer:

Explanation:

Hello,

In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:

\rho=1.24*1g/mL=1.24g/mL

In such a way, since the given solution of nitric acid is 64 % by mass, we've got:

\frac{64gHNO_3}{100g\ solution}

Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:

M=\frac{(100g-64g)HA}{100g\ solution}*\frac{1.24g\ solution }{1mL \ solution}*\frac{1000mL\ solution}{1L\ solution}*\frac{1molHA}{90.2gHA}   \\\\M=4.95M

Regards.

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Describe the best method for separating a mixture of sand, salt, and steel shavings by placing the steps below in the correct or
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Which of the following compounds is likely to have a pH above 7?
Shkiper50 [21]

Answer:

koh

Explanation:

kOh has a ph level of 10.89

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A scientist measures the standard enthalpy change for the following reaction to be 67.9 kJ:
hodyreva [135]

Answer:

-252.5 kJ/mol = ΔH H2O(g)

Explanation:

ΔH Fe2O3 = -825.5kJ/mol

ΔH H2 = 0kJ/mol

ΔH Fe = 0kJ/mol

Based on Hess's law, ΔH of a reaction is the sum of ΔH of products - ΔH of reactants. For the reaction:

Fe2O3(s) + 3 H2(g) →2Fe(s) + 3 H2O(g)

ΔHr = 67.9kJ/mol = 3*ΔH H2O + 2*ΔHFe - (ΔH Fe2O3 + 3*Δ H2)

67.9kJ/mol = 3*ΔH H2O + 2*0kJ/mol - (ΔH -825.5kJ/mol + 3*Δ H2)

67.9 = 3*ΔH H2O(g) + 825.5kJ/mol

-757.6kJ/mol = 3*ΔH H2O(g)

<h3>-252.5 kJ/mol = ΔH H2O(g)</h3>
6 0
3 years ago
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