Question

Helppp!!!!! Please!!

Answer 1

Answer:

• The impulse exerted by the ball is 7.2 kg.m/s

• The average force exerted on the ball by the bat is 600 N.

Explanation:

Given;

mass of the baseball, m = 0.144 kg

velocity of the baseball, v₁ = 20 m/s

velocity of the batter, v₂ = -30 m/s (opposite direction to the ball's speed)

The impulse exerted by the ball is calculated as follows;

J = ΔP = mv₁ - mv₂

ΔP = m(v₁ - v₂)

ΔP = 0.144 [20 - (-30)]

ΔP = 0.144 ( 20 + 30 )

ΔP = 0.144 (50)

ΔP = 7.2 kg.m/s

The average force exerted on the ball by the bat is calculated as;

$F = \frac{\Delta P }{t} \\\\where; t \ is \ time \ of \ contact= 0.012 \ s\\\\F = \frac{7.2}{0.012} \\\\F = 600 \ N$