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Salsk061 [2.6K]
3 years ago
9

A(n)_____ is a device that provides the power and motion to manipulate the moving parts of a valve or damper used to control flu

id flow. A. actuator B. pilot-operated regulator C. ratio regulator D. sliding stem
Engineering
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

Out of the four options provided

option A. actuator

is correct

Explanation:

An actuator is the only device out of the four mentioned devices that provides power and ensures the motion in it in order to manipulate the movement of the moving parts of the damper or a valve used whereas others like ratio regulator are used to regulate air or gas ratio and none mof the 3 remaining options serves the purpose

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Explanation:

I'm positive this answer is correct! :)

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5 0
3 years ago
Propyl Benzhydryl Ether (continued on next page):
uranmaximum [27]

Answer:

See detailed explanation and image attached

Explanation:

1 mole of 1-pentanol reacts with 1 mole of benzhydrol

Number of moles in 1.5 g of benzhydrol = mass/molar mass = 1.5 g/184 g/mol = 0.008 moles of benzhydrol

x moles of 1-pentanol reacts with 0.008 moles of benzhydrol

x = 0.008 moles of 1-pentanol

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0.008 moles occupies 22.4 * 0.008 moles = 0.179 L of 1-pentanol is required.

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6 0
3 years ago
The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a sti
MA_775_DIABLO [31]

Answer:

L = 4.574 ft

Explanation:

Given:

- The weight of the block W = 2 lb

- The initial velocity of the block v_i = 0

- The stiffness of the spring k = 2 lb/ft

- The radius of the cylindrical surface r = 2 ft

Find:

Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.

Solution:

- Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.

                           F_n = m*a_n

Where, a_n is the centripetal acceleration or normal component of acceleration as follows:

                           a_n = v^2_2 / r

- Substitute:

                          F_n = m*v^2_2 / r

Where, F_n normal force acting on block by the surface is:

                          F_n = W*cos(θ)

- Substitute:

                          W*cos(θ) = m*v^2_2 / r

                          v_2 = sqrt ( r*g*cos(θ) )

- Plug in the values:

                          v^2_2 = 2*32.2*cos(60)

                          v^2_2 = 32.2 (ft/s)^2

- Apply the conservation of energy between points A and B where θ= 60° :

                      T_A + V_A = T_B + V_B

Where,

                      T_A : Kinetic energy of the block at inital position = 0

                      V_A: potential energy of the block inital position

                      V_A = 0.5*k*x_A^2

                      x_A = 2*pi - L            ..... ( L is the original length )

                      V_A = 0.5*2*(2*pi - L)^2 =(2*pi - L)^2

                      T_B = 0.5*W/g*v_2^2 = 0.5*2 / 32.2 *32.2 = 1

                      V_B = 0.5*k*x_B^2 + W*2*cos(60)

                      x_B = 2*0.75*pi - L            ..... ( L is the original length )

                      V_B = 0.5*2*(1.5*pi - L)^2 + 2*1 = 2 + ( 1.5*pi - L )^2

- Input the respective energies back in to the conservation expression:

                      0 + (2*pi - L)^2 = 1 + 2 + ( 1.5*pi - L )^2

                      4pi^2 - 4*pi*L + L^2 = 3 + 2.25*pi^2 - 3*pi*L + L^2

                      pi*L = 1.75*pi^2 - 3

                         L = 4.574 ft

                         

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Answer is given below

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