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just olya [345]
3 years ago
8

URGENT

Physics
1 answer:
natka813 [3]3 years ago
3 0

Answer:

{ \tt{velocity = \frac{distance}{time}}}  \\  \\ { \tt{velocity =  \frac{2750}{10.5} }} \\  = { \tt{261.9 \:  {ms}^{ - 1} }}

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The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal re
inna [77]

Answer:

Explanation:

The thermal efficiency of a Power cycle \eta = \dfrac{Q_H -Q_c}{Q_H}

where;

\eta = 50\% = 0.5

Q_H = Heat \ flow \ from \ higher \ temperature

Q_c = Heat \ flow \ from \ lower \ temperature

0.5 = \dfrac{Q_H -Q_c}{Q_H}

0.5 Q_H = Q_H - Q_c --- (1)

Q_c = 0.5 Q_H         ---- (2)

The coefficient of performance is:

COP_R = \dfrac{Q_c}{Q_H -Q_c}

let replace the value of Q_c = 0.5 Q_H   in the above equation then;

COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}

COP_R = \dfrac{0.5Q_H}{0.5 Q_H}

COP_R = 1

The

On the other hand,  the heat pump

COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}

By replacing equation (1) into the above equation; we have:

COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}

COP_{HP} = \dfrac{1}{0.5}

COP_{HP} =2

t

5 0
3 years ago
A speeding truck travels in the positive x direction. It hits a car traveling in the positive y direction. The vehicles are defo
marusya05 [52]

Answer:

B. Kinetic energy of the system is partially used up in the deformation of the vehicles.

Explanation:

In an inelastic collision, momentum is conserved, but kinetic energy is not. Kinetic energy is lost as heat or lost in the deformation of the objects.

5 0
3 years ago
Read 2 more answers
An instrument is defective for all of the following conditions EXCEPT:_______
NARA [144]

Answer:

I believe its C

6 0
4 years ago
A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center
uranmaximum [27]

Answer:

4.36 rad/s

Explanation:

Radius of platform r = 2.97 m

rotational inertia I = 358 kg·m^2

Initial angular speed w = 1.96 rad/s

Mass of student m = 69.5 kg

Rotational inertia of student at the rim = mr^2 = 69.5 x 2.97^2 = 613.05 kg.m^2

Therefore initial rotational momentum of system = w( Ip + Is)

= 1.96 x (358 + 613.05)

= 1903.258 kg.rad.m^2/s

When she walks to a radius of 1.06 m

I = mr^2 = 69.5 x 1.06^2 = 78.09 kg·m^2

Rotational momentuem of system = w(358 + 78.09) = 436.09w

Due to conservation of momentum, we equate both momenta

436.09w = 1903.258

w = 4.36 rad/s

7 0
3 years ago
Can some one help me with this so i can bring my grade up
777dan777 [17]

Answer:

a

Explanation:

3 0
3 years ago
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