Answer:
Explanation:
The polarity of the 3 compounds would be in the order of
Ferrocene < Acetylferrocene < Diacetylferrocene
Your TLC data has to also support this observation . This can be checked by measuring the values of Rf ( Retention factor = distance travelled by solute/solvent ) .The Rf values also has to follow this particular order: -
Ferrocene > acetylferrocene > diacetylferrocene
2) Hexane happens to be a non-polar solvent. The polarity of hexane can be increased if some polar solvents for example, ethyl and methylene chloride etc are added
Therefore, in the increasing order of solvents polarity, we have
Hexane < 1:1 mixture of hexane: methylene chloride < 9:1 mixture of methylene chloride:
3) Chromatographic techniques all have a stationary phase in addition to a mobile phase. In the case of column chromatography, the silica gel will be the stationary phase and the solvent that will be poured will be the mobile phase.
4) The TLC and column chromatography both happen to have the same stationary phase which is the silica gel. Also, the same solvent mixture is used in both the techniques. This makes the result of the 2 to be almost the same. The difference seen between them is that, TLC works against the gravity while on the other hand column chromatography works in the direction of the gravity.
5) The key feature in the IR spectra of the acetylferrocene that will be absent in the spectra of ferrocene is the presence of carbonyl stretching frequency at close to 1700 per cm(cm-1). This peak is easily differentiated between both acetyl ferrocene and ferrocene.
Answer:
They had a negative charge
Explanation:
Answer:
Atom 3
Explanation:
Protons have a +1 charge, electrons have a -1 charge, and neutrons have no charge and are therefore neutral. The charges will cancel each other when equal. To determine which atom has the a -1 charge, find the atom that has one more electron than it has protons.
2NaOH + ZnCl2 → 2NaCl + Zn(OH)2
Zn(OH)2 is your precipitate.
No. of moles of NaOH = 2.50X50.0÷1000 = 0.125mol
2mol of NaOH reacted to produce 1 mol of Zn(OH)2.
No. of moles of Zn(OH)2 produced when 0.125mol of NaOH reacted
= 0.125 x 1 ÷ 2
= 0.0625mol
Mass of Zn(OH)2 = 0.0625 x [65.4+2(16+1)] = 6.21g
