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3 years ago

Simone is walking her dog on a leash. The dog is pulling with a force of 32 N to the right and Simone is pulling

Physics

2 answers:

crimeas [40]3 years ago

6 0

1. 16

2.unbalanced

3.forward

levacccp [35]3 years ago

5 0

Answer:

net force=16

It is a balance force

There Dog will move forward

Explanation:

net force=32-16

net force=16N

It is a balanced force

The dog will move forward since the force the dog is applying is larger than Simone's force

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A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

3 0

3 years ago

2. A woman prevents a 3kg brick from falling by pressing it against a vertical wall. The coefficient of friction

Anettt [7]

<h3>Answer:</h3>

49 N

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of the brick as 3 kg
The coefficient of friction as 0.6

We are required to determine the force that must be applied by the woman so the brick does not fall.

We need to importantly note that;
For the brick not to fall the, the force due to gravity is equal to the friction force acting on the brick.

That is; Friction force = Mg

But; Friction force = μ F

Therefore;

μ F = mg

0.6 F = 3 × 9.8

0.6 F = 29.4

F = 49 N

Therefore, she must use a force of 49 N

6 0

3 years ago

An electron moves at a speed of 1.0 x 104 m/s in a circular path of radius 2 cm inside a solenoid. The magnetic field of the sol

iogann1982 [59]

Answer:

(a) B = 2.85 × $10^{-6}$ Tesla

(b) I = I = 0.285 A

Explanation:

a. The strength of magnetic field, B, in a solenoid is determined by;

r = $\frac{mv}{qB}$

⇒ B = $\frac{mv}{qr}$

Where: r is the radius, m is the mass of the electron, v is its velocity, q is the charge on the electron and B is the magnetic field

B = $\frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }$

= $\frac{9.11*10^{-27} }{3.2*10^{-21} }$

B = 2.85 × $10^{-6}$ Tesla

b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;

B = μ I N/L

⇒ I = B ÷ μN/L

where B is the magnetic field, μ is the permeability of free space = 4.0 × $10^{-7}$ Tm/A, N/L is the number of turns per length.

I = B ÷ μN/L

= $\frac{2.85*10^{-6} }{4*10^{-7} *25}$

I = 0.285 A

5 0

3 years ago

To do the same amount of work in less time you need to

Dima020 [189]

Answer:

requires more power

Explanation:

5 0

3 years ago

a radio antenna broadcasts a 1.0 MHz radio wav e with 21 kW of power. Assume that the radiation is emitted uniformly in all dire

My name is Ann [436]

Answer:

$I=2.67\times 10^{-6}\ W/m$

Explanation:

Given that,

Frequency of a radio antenna is 1 MHz

Power, P = 21 kW

We need to find the the waves intensity 25 km from the antenna . The object emits intenisty evenly in all direction. It can be given by :

$I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{21\times 10^3}{4\pi (25000)^2}\\\\I=2.67\times 10^{-6}\ W/m$

So, the wave intensity 25 km from the antenna is $2.67\times 10^{-6}\ W/m$ .

5 0

3 years ago