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hoa [83]
3 years ago
6

A 2100 lb (1 kg=2.2 lbs) car is using 4500 N of traction in order to move with a constant

Physics
1 answer:
vredina [299]3 years ago
4 0

Answer:

a = 0\ m/s^2

Explanation:

The acceleration of a body is defined as the change in velocity of an object, with respect to time. So, in order to produce and acceleration in any object, the velocity of that object must change. And, if the velocity of the object is not changing with respect to time, then the object is said to have a uniform motion. The acceleration of the object in such uniform motion is always zero. Because the change in velocity is zero.

acceleration = change in velocity/time\\acceleration = 0 / time\\acceleration = 0 m/s^2

Since, the car in this case is moving with a constant speed. Therefore, its acceleration will also be zero.

<u>a = 0 m/s²</u>

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"The position of each element in the table gives important information about its structure, properties, and behavior in chemical reactions. Specifically, an element's position in the periodic table helps you figure out its electron configuration, how the electrons are organized around the nucleus."

7 0
3 years ago
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
3 years ago
Examples of energy balance: physical education
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Answer:children burn calories to being a student  

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3 years ago
PLS HELP THIS IS DUE TODAY!!!!!!!!!
Juli2301 [7.4K]

The speed at which the objects were attracted to each other determined by the gravitational pull.

<h3>What is gravity?</h3>

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity or gravitational pull.

The gravitational force, Fg is the attractive force exerted by the Earth on the object that is equal to the mass of the object times the gravitational acceleration.

When the two objects are attracted, the speed with which they are moving toward each other depends on the strength of the pull force. This pull force is the gravitational pull.

Thus, the speed at which the objects were attracted to each other determined by the gravitational pull.

Learn more about gravity.

brainly.com/question/4014727

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3 0
2 years ago
Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed o
kobusy [5.1K]

Answer:

\Delta \lambda=14.3\ nm

Explanation:

It is given that,

The number of lines per unit length, N = 900 slits per cm

Distance between the formed pattern and the grating, l = 2.3 m

n the first-order spectrum, maxima for two different wavelengths are separated on the screen by 2.98 mm, \Delta Y=2.98\ mm = 0.00298\ m

Let d is the slit width of the grating,

d=\dfrac{1}{N}

d=\dfrac{1}{900\ cm}

d=1.11\times 10^{-5}\ m

For the first wavelength, the position of maxima is given by :

y_1=\dfrac{L\lambda_1}{d}

For the other wavelength, the position of maxima is given by :

y_2=\dfrac{L\lambda_2}{d}

So,

\Delta \lambda=\dfrac{\Delta y d}{l}

\Delta \lambda=\dfrac{0.00298\times 1.11\times 10^{-5}}{2.3}

\Delta \lambda=1.43\times 10^{-8}\ m

or

\Delta \lambda=14.3\ nm

So, the difference between these wavelengths is 14.3 nm. Hence, this is the required solution.

3 0
3 years ago
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