The Bohr Model, which was proposed by Niels Bohr in 1913
The energy change when the temperature of 0.750 kg of water decreased from 123 °C to 23.0 °C is -313.5 kJ.
In this problem, we are dealing with specific heat which is referred to as the sum of heat per unit mass required to raise the temperature by one degree Celsius.Since we know the boiling point of water is 100°C, at 123°C, the water is steam.
The formula we are referring to for calculating the heat energy Q
Q= m C ΔT
where m is the mass of water which is equal to 0.750 Kg, then
C is the specific heat of water equal to 4180 J/Kg °C and
ΔT is the change in temperature which is (23-123)= -100°C
So, assembling those desired values on the formula we get,
Q= 0.750 (4180) (-100)
Q=-313500
= -313.5 kJ
To know more about specific heat refer to the link brainly.com/question/13163208?referrer=searchResults.
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The answer is:
It will float
In order to determine the formula of the hydrate, [Anhydrous Solid⋅xH2O], the number of moles of water per mole of anhydrous solid (x) will be calculated by dividing the number of moles of water by the number of moles of the anhydrous solid (Equation 2.12.
Natural, Organic & Manmade Fibers. after flame is out there is a soft gray ash!
