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3 years ago

Which object has the MOST gravity in the solar system?

Chemistry

2 answers:

Serggg [28]3 years ago

7 0

Answer: Jupiter.

Explanation: <u>Jupiter is the largest and most massive planet in the Solar System. Its mean radius, at 69,911 ± 6 km, makes it 10.97 the times the size of Earth, while its mass (1.8986×1027 kg) is the equivalent of 317.8 Earths.</u>

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faltersainse [42]3 years ago

5 0

Answer:

Jupiter

Explanation:

It is 2.5 times on what we experience on earth, it’s just depends on 3 things the density, mass and size

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Hydrogen + copper(II) oxide= copper + steam, which substance is oxidized. explain your answers

Vsevolod [243]

Hydrogen is oxidized. The H2 reactant has an oxidation number of 0 because it’s in its elemental form. In the H2O product, H has an oxidation number of +1. The increase in oxidation number is oxidation.

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2 years ago

If you burn 22.4 22.4 g of hydrogen and produce 2.00 × 10 2 2.00×102 g of water, how much oxygen reacted?

Mnenie [13.5K]

Answer:

179.2g of O2

Explanation:

Fir, we must obtain a balanced equation for the reaction.

The equation for the reaction is:

2H2 + 02 —> 2H2O

Next, we find the molar mass of H2 and O2 as shown below:

Molar Mass of H2 = 2x1 = 2g/mol

Mass conc. of H2 from the balanced equation = 2 x 2 = 4g

Molar Mass of O2 =16x2 = 32g/mol

From the equation,

4g of H2 required 32g of O2,

Therefore 22.4g of H2 will require = (22.4x32)/4 = 179.2g of O2

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3 years ago

What type and how many atoms is ethyl butyrate made of?

liberstina [14]

Answer: 45

Explanation: thats what i have in my notes

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2 years ago

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bixtya [17]

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2 years ago

Read 2 more answers

A 0.0250L solution of HCl is neutralized by 0.0780L of an unknown Mg(OH)2 solution. Also 0.050L of this Mg(OH)2 solution is neut

Ilya [14]

Answer:

$M_{HCl} = 1.12M$

Explanation:

Hello!

In this case, for the first reaction we need to focus on, the neutralization of magnesium hydroxide by phosphoric acid, we can write up the following equation:

$3Mg(OH)_2+2H_3PO_4\rightarrow Mg_3(PO_4)_2+6H_2O$

Whereas the acid and base react in a 3:2 mole ratio; thus, we can write:

$2M_{Mg(OH)_2}V_{Mg(OH)_2}=3M_{H_3PO_4}V_{H_3PO_4}$

Now, solving for the concentration of the magnesium hydroxide solution we get:

$M_{Mg(OH)_2}=\frac{3M_{H_3PO_4}V_{H_3PO_4}}{2V_{Mg(OH)_2}} \\\\M_{Mg(OH)_2}=\frac{3*0.20M*0.0300L}{2*0.050L}=0.18M$

Now, for the reaction between hydrochloric acid and magnesium hydroxide we have:

$Mg(OH)_2+2HCl\rightarrow MgCl_2+2H_2O$

$2M_{Mg(OH)_2}V_{Mg(OH)_2}=M_{HCl}V_{HCl}$

Therefore, solving for the concentration of the hydrochloric acid solution we get:

$M_{HCl}=\frac{2M_{Mg(OH)_2}V_{Mg(OH)_2}}{V_{HCl}} \\\\M_{HCl}=\frac{2*0.18M*0.078L}{0.025L}\\\\M_{HCl} = 1.12M$

Best regards!

6 0

2 years ago