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photoshop1234 [79]
3 years ago
7

Explain the effect of pressure on the following chemical equation :

Chemistry
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

Explanation:

One

Pressure will favor the side with the least number of mols if it the larger number of moles counts only the gases. (Le Chetalier's Principle). In this case both CaCO3 and CaO are not soluble in water. The only gas is CO2. Since it represents the most number of mols the reactant is favored.

More or Less are very troublesome words in beginning science. Make sure you understand their meaning for this question. The more pressure applied, the more the reactants will be favored and the equation shifts left.

Two

Fe and Fe3O4 are both solids. It depends on the form that water takes. Looking it up, it is shown to be in a gas form. That means if you increase the pressure, nothing will happen. That is not your question, but you should note it.

The answer to your question is you increase the concentration of Fe or H2O, the equilibrium will shift right.

If you add more Fe3O4 or hydrogen it will shift left.

Chemists say that if you alter the equilibrium the equation will shift in the opposite direction to compensate for the action you have taken.

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Typically, a solid chloride unknown (not the AgCl product) for analysis is dried in an oven to remove absorbed water before the
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Answer:

%Cl would be too high if not dried.

Explanation:

Cl (chlorine) is a liquid. During the process of drying AgCl, the chlorine particles evaporate and chlorine is lost.

7 0
3 years ago
A first-order reaction (A → B) has a half-life of 25 minutes. If the initial concentration of A is 0.900 M, what is the concentr
Oksanka [162]

Answer:

0.6749 M is the concentration of B after 50 minutes.

Explanation:

A → B

Half life of the reaction = t_{1/2}=25 minutes

Rate constant of the reaction = k

For first order reaction, half life and half life are related by:

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{25 min}=0.02772 min^{-1}

Initial concentration of A = [A]_o=0.900 M

Final concentration of A after 50 minutes = [A]=?

t = 50 minute

[A]=[A]_o\times e^{-kt}

[A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}

[A] = 0.2251 M

The concentration of A after 50 minutes = 0.2251 M

The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M

0.6749 M is the concentration of B after 50 minutes.

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The most penetrating neclear radiation is
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Radioactive is the most penetrating nuclear radiation
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If one or more nucleotide pairs are deleted from a dna strand, this is known as a:_________
Leya [2.2K]

If one or more nucleotide pairs are deleted from a DNA strand, this is known as a frameshift mutation

<h3>Define Frameshift Mutation</h3>

Insertions or deletions in the genome that are not multiples of three nucleotides are referred to as frameshift mutations. They are a particular class of insertion-deletion (indel) alterations that are present in polypeptides' coding sequences. Here, there are no multiples of three in the number of nucleotides that are added to or subtracted from the coding sequence. They may result from really basic alterations like the insertion or deletion of a single nucleotide.

<h3>Frameshift mutations' effects</h3>

One of the most harmful modifications to a protein's coding sequence is a frameshift mutation. They are quite prone to produce non-functional proteins that frequently interfere with a cell's metabolic processes and result in significant alterations to polypeptide length and chemical makeup. Frameshift mutations can cause the mRNA to stop translating too soon and create an extended polypeptide.

Learn more about Frameshift mutations here:-

brainly.com/question/12732356

#SPJ4

4 0
1 year ago
Based on the article "Will the real atomic model please stand up?,” describe one major change that occurred in the development o
nydimaria [60]
I don't know this article, but I do know some major changes: first, the change from the plum pudding model (no nucleus, just electrons) to the gold foil experiment, which had Rutherford shoot alpha particles at a sheet of gold only to find them rebounding, proving the existence of a positively charged mass, i.e a nucleus, in the atom. However, this changed again when Bohr realized that the negatively charged electrons should be attracted to the positively charged center, so that there must be something else inside the nucleus. 
3 0
3 years ago
Read 2 more answers
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