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3 years ago

Why will light from the sun change the color of the cloth when the light from the desk lamp does not

Physics

1 answer:

mixas84 [53]3 years ago

3 0

Answer:

Because the sun gives off a type of light that carries energy, and light from the desk lamp does not.

Explanation:

All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays. Radiation is one way to transfer heat.

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A football player with a mass of 85 kg wears a uniform and helmet that have a mass of 4.5 kg. The football player moves at 2.1 m

DochEvi [55]

The answer would be 187.95 kg.m/s.

To get the momentum, all you have to do is multiply the mass of the moving object by the velocity.

p = mv

Where:
P = momentum
m = mass
v = velocity

Not the question is asking what is the total momentum of the football player and uniform. So we need to first get the combined mass of the football player and the uniform.

Mass of football player = 85.0 kg
Mass of the uniform = <u> 4.5 kg</u>
TOTAL MASS 89.5 kg

So now we have the mass. So let us get the momentum of the combined masses.

p = mv
= (89.5kg)(2.1m/s)
= 187.95 kg.m/s

5 0

3 years ago

Read 2 more answers

A 0.50-kg block attached to an ideal spring with a spring constant of 80 N/m oscillates on a horizontal frictionless surface. Th

wolverine [178]

Answer:

Explanation:

easy way

when system is all kinetic energy, velocity is at a maximum

E = ½mv²

v = √(2E/m) = √(2(25)/0.5) = √100 = 10 m/s

harder way

ω = √(k/m) = √(80/0.5) = √160 rad/s

When the system is entirely spring potential, the amplitude A is

E = ½kA²

A = √(2E/k) = √(2(25)/80) = 0.790569... = 0.79 m

maximum velocity is ωΑ = 0.79√160 = 10 m/s

6 0

3 years ago

1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car e

tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 $m/s^{2}$

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5 $m/s^{2}$

6 0

3 years ago

A carousel is moving with uniform circular motion. The centripetal acceleration of the ride is * 1 point circular

finlep [7]

> A carousel is moving with uniform circular motion. The centripetal acceleration of the ride is:

Centripetal acceleration is always directed toward the center of motion

> Where should a force be applied on a lever arm to produce the most torque?

farthest from the axis of rotation

> A boy can raise a rock that weighs 120 N by using a lever and applying a force of 25 N.

What is the mechanical advantage of the lever?

Simply divide the weight by the force applied:

120 / 25 = 4.8

> A pebble that is 3.81 m from the eye of a tornado has a tangential speed of 124 m/s. What is the magnitude of the pebble's centripetal acceleration?

Centripetal acceleration is calculated using the formula:

a = v^2 / r

a = (124 m/s)^2 / 3.81 m

a = 4,035.70 m/s^2 ~ 4036

> A dog sits 1.25 m from the center of a merry go round and revolves at a tangential speed of 2.0 m/s. If the dog's mass is 19.3 kg, what is the magnitude of the centripetal force on the dog?

a = v^2 / r

a = (2.0 m/s)^2 / 1.25 m

a = 3.2 m/s^2

The force is:

F = m a

F = 19.3 kg * 3.2 m/s^2

F = 61.8 N

> A ball attached to a string is whirled in a circle. If the string breaks, what causes the ball to move in a straight line?

The force which is directed away from the center of the motion: centrifugal force

> Find the magnitude of the gravitational force exerted on a 66.5 kg astronaut on the surface of Planet X if the planet has a radius of 4.40 x 10⁶ m and a mass of 8.43 x 10²³ kg.(Use G= 6.67 x 10⁻¹¹ Nm/kg²)

We use the formula:

F = G m1 m2 / r^2

F = 6.67 x 10⁻¹¹ Nm/kg² * (66.5 kg) * (8.43 x 10²³ kg) / (4.40 x 10⁶ m)^2

F = 193 N

> How would the speed of the Earth's orbit change if the Earth's distance from the Sun increased by 9 times?

The orbital speed is related to distance from the formula:

v = sqrt (GM / r)

where r is the distance from Earth to Sun

so if r’ = 9 r

v = sqrt (GM / 9r)

v = (1/3) sqrt (GM / r)

Therefore: Decrease by a factor of 3

> What is the efficiency of a crane that requires 28,000 J of energy to lift a 200 kg object 10 meters?

The total work done is:

Work = 200 kg * 9.8 m/s^2 * 10 m

Work = 19,600 J

So efficiency is:

efficiency = 19,600 / 28,000 * 100% = 70%

> What is the force required to produce a 1.4 Nm torque when applied to a door at a 60.0º angle and 0.40 m from the hinge?

The perpendicular component of the applied force is:

F * sin(60°) = 0.866F N

Since the moment arm is 0.40 m, the torque is:

(0.866F N)*(0.4 m) = 0.3464F N-m

This torque is equal to a value of 1.4 N-m, therefore

0.3464F = 1.4

F = 4.0 N

3 0

3 years ago

The greater the mass is in an object, the higher resistance to a change in movement the object will have. Please select the best

Fofino [41]

This statement is true. The greater the mass is in an object, it is indeed the higher resistance to a change in movement the object will have. That only mean that the mass of an object and its resistance to change of movement is directly proportional.

3 0

3 years ago