Question

If the specific heat of methanol is 32.91 J/K. g. how many joules are necessary to raise the temperature of 120 g of methanol from 24 0C to 98 0C?

Answer 1

Answer:

$Q=292240.8J=292.2kJ$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to use the general heat equation:

$Q=mC(T_2-T_1)$

For us to plug the given mass, specific heat and temperature change to obtain the required heat:

$Q=120g*32.91\frac{J}{g*K} (98\°C-24\°C)\\\\Q=292240.8J=292.2kJ$

Regards!