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Olin [163]
3 years ago
6

A vector makes an angle, theta, with the horizontal. The horizontal and vertical components of the vector will be equal in magni

tude if the angle theta is
1 point
a.90°
b.60°
c.45°
d.30°
Physics
2 answers:
nika2105 [10]3 years ago
8 0

Answer:

The correct option is;

c. 45°

Explanation:

The given information is that the angle the vector makes with the horizontal = θ

Let the magnitude of the resultant vector = R

The horizontal component of the vector are given as follows;

Rₓ = R × cos(θ)

The vertical component of the vector are given as follows;

R_y = R × sin(θ)

The resultant vector, R, in vector form, R, is the sum of the horizontal and vertical components as follows;

R = R × cos(θ)·i + R × sin(θ)·j

Therefore;

The horizontal and vertical component will be equal when cos(θ) = sin(θ)

Given that tan(θ) = sin(θ)/cos(θ), we have that when cos(θ) = sin(θ), tan(θ) = sin(θ)/cos(θ) = sin(θ)/sin(θ) = 1

tan(θ) = 1,

∴ θ = tan⁻¹(1) = 45°

θ = 45°.

CaHeK987 [17]3 years ago
6 0

Answer:

c. 45°

Explanation:

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A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal. If the whale continues in a s
charle [14.2K]

Answer:

It is 68.404 m deep.

Explanation:

The motion of the whale can be seen in the form of a right-angle triangle.

Angle of deviation = 20°

We know that, sinФ = Perpendicular/ Hypotenuse.

Here, hypotenuse = 200 m

Depth is perpendicular that we have to find.

sin(20°) = Depth/200

Depth = sin(20°) * 200 = 68.404 meters.

8 0
4 years ago
Read 2 more answers
Calculate the number of free electrons per cubic meter for some hypothetical metal, assuming that there are 1.3 free electrons p
boyakko [2]

Answer:

The number of free electrons per cubic meter is 7.61\times 10^{28}\ m^{-3}

Explanation:

It is given that,

The number of free electrons per cubic meter is, 1.3

Electrical conductivity of metal, \sigma=6.8\times 10^7\ \Omega^{-1}m^{-1}

Density of metal, \rho=10.5\ g/cm^3

Atomic weight, A = 107.87 g/mol

Let n is the number of  free electrons per cubic meter such that,

n=1.3\ N

n=1.3(\dfrac{\rho N_A}{A})

Where

\rho is the density of silver atom

N_A is the Avogadro number

A is the atomic weight of silver

n=1.3\times (\dfrac{10.5\ g/cm^3\times 6.02\times 10^{23}\ atoms/mol}{107.87\ g/mol})

n=7.61\times 10^{22}\ cm^{-3}

or

n=7.61\times 10^{28}\ m^{-3}

Hence, this is the required solution.

6 0
3 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
A block of gelatin is 120mm by 120mm by 40mm whrn unstressed. A force of 49N is applied tangentially to the upper surface causin
Inessa05 [86]

Answer:

The shearing stress is 10208.3333 Pa

The shearing strain is 0.25

The shear modulus is 40833.3332 Pa

Explanation:

Given:

Block of gelatin of 120 mm x 120 mm by 40 mm

F = force = 49 N

Displacement = 10 mm

Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain​, SS = ?

The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:

A = 40*120 = 4800 mm² = 0.0048 m²

The shearing stress:

Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa

The shearing strain is defined as the tangent of the displacement that the block over its length:

SS=tan\theta =\frac{Displacement}{L}  =\frac{10}{40} =0.25

Finally, the shear modulus is the division of the shearing stress over the shearing strain:

Sm=\frac{10208.3333}{0.25} =40833.3332Pa

6 0
4 years ago
Can u pls help me .....
andrew-mc [135]

Answer:

the floor absorb the water so the water is dry

5 0
3 years ago
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