Answer:
0.00369 moles of HCl react with carbonate.
Explanation:
Number of moles of HCl present initially =
moles = 0.00600 moles
Neutralization reaction (back titration): 
According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.
So, excess number of moles of HCl present = number of NaOH added for back titration =
moles = 0.00231 moles
So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles
Hence, 0.00369 moles of HCl react with carbonate.
Answer:
33.3 g AlCl3
Explanation:
First:
You need a balanced chem equation.
2Al + 3Cl2 --->2AlCl3
So now you use this to set up train track method which helps us cancel out the units. Also we dont care about chlorine because it is excess.
6.73g Al x 1mol Al/26.98g Al x 2mol AlCl3/2molAl x 133.34g AlCl3/1molAlCl3
= 33.3 g AlCl3
Hi, P.S. The atomic number will always be the same as the number of protons...
For the Venn diagram, freezing water should be in the physical category (A)