Question

A stone is thrown upward with a kinetic energy of 10J. If it goes up to a maximum height of 5 m, find the initial velocity and mass of the stone ​

Answer 1

Answer:

Explanation:

Begin by remembering that at the stone's max height, the final velocity there is 0. Being in possession of that information along with the fact that the pull of gravity due to acceleration is -9.8 m/s/s, we can use the equation

$v^2=v_0^2+2a$Δx where v is the final velocity, v₀ is the initial velocity, a is the pull of gravity, and Δx is the displacement. Filling in:

$0^2=v_0^2+2(-9.8)(5.0)$

0 = v₀² - 98 so

98 = v₀² and

v = 9.9 m/s Now we can put that into the KE equation.

$10=\frac{1}{2}m(9.8)$ and

$m=\frac{2(10)}{98}$ so

m = .20 kg