Answer:
Final molarity of iodide ion C(I-) = 0.0143M
Explanation:
n = (m(FeI(2)))/(M(FeI(2))
Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol
So n = 0.981/309.85 = 0.0031 mol
V(solution) = 150mL = 0.15L
C(AgNO3) = 35mM = 0.035M = 0.035m/L
n(AgNO3) = C(AgNO3) x V(solution)
= 0.035 x 0.15 = 0.00525 mol
(AgNO3) + FeI(3) = AgI(3) + FeNO3
So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol
C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M
Answer:
The temperature and pressure below which a supercritical fluid exists.
Explanation:
Critical point is a region on the phase diagram where fluid phases (liquids and gases) have the equal density.
This is caused by increased temperature and pressure of the fluid particles in a confided container. Supercritical fluids exist in a state above critical point.
I hope this explanation was clear.
I) cc14
ii) h20
iii) i’m not sure
not fully sure but hope this helps!
Answer:
1.1 M
General Formulas and Concepts:
- Molarity = moles of solute / liters of solution
Explanation:
<u>Step 1: Define variables</u>
1.2 mol KCL
1.1 L of solution
M = unknown
<u>Step 2: Solve for Molarity</u>
- Substitute: M = 1.2 mol/1.1 L
- Evaluate: M = 1.09091
<u>Step 3: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules.</em>
1.09091 M ≈ 1.1 M
