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Darya [45]
3 years ago
14

Viteza unui mobil care se deplasează cu accelerație constantă crește de la 3,2 m/s la 5,2 m/s în timp de 8 s. Accelerația mobilu

lui este :
Engineering
1 answer:
Verizon [17]3 years ago
3 0

Answer:

a=0.25\ m/s^2

Explanation:

Initial speed of the mobile = 3.2 m/s

Final speed of the mobile = 5.2 m/s

Time, t = 8 s

We need to find the acceleration of the mobile. It can be given by the change in velocity divided by time. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(5.2-3.2)\ m/s}{8\ s}\\\\=0.25\ m/s^2

So, the acceleration of the mobile is 0.25\ m/s^2.

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A pipe is insulated such that the outer radius of the insulation is less than the critical radius. Now the insulation is taken o
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7 0
3 years ago
FD=CD*((P*(V^2)*A)/2)<br><br>Please solve for V
REY [17]

Answer:

The answer is V = √2FD ÷ CD × PA

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<u>-TheUnknownScientist 72</u>

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