Answer:
320 mmol
Explanation:
405.0 mL * 1L/1000 mL = 0.4050 L
0.79 M = 0.79 mol/L
0.79 mol/L * 0.4050 L=0.32 mol
0.32 mol * 10^3 mmol/1 mol = 320 mmol
Answer;
294.13 amu
Solution;
-293nv is 293.10 amu and that of 295nv is 295.45 amu
293.05+295.2=588.25
588.25/2= 294.13 amu
an amu of 294.13 using significant figures
V(NaOH)*M(NaOH)=V(HCOOH)M(HCOOH)
35.43ml*0.1150m=20.00ml*M(HCOOH)
M(HCOOH)=0.2037m
