Answer:
23.3808 kW
20.7088 kW
Explanation:
ρ = Density of oil = 800 kg/m³
P₁ = Initial Pressure = 0.6 bar
P₂ = Final Pressure = 1.4 bar
Q = Volumetric flow rate = 0.2 m³/s
A₁ = Area of inlet = 0.06 m²
A₂ = Area of outlet = 0.03 m²
Velocity through inlet = V₁ = Q/A₁ = 0.2/0.06 = 3.33 m/s
Velocity through outlet = V₂ = Q/A₂ = 0.2/0.03 = 6.67 m/s
Height between inlet and outlet = z₂ - z₁ = 3m
Temperature to remains constant and neglecting any heat transfer we use Bernoulli's equation
![\frac {P_1}{\rho g}+\frac{V_1^2}{2g}+z_1+h=\frac {P_2}{\rho g}+\frac{V_2^2}{2g}+z_2\\\Rightarrow h=\frac{P_2-P_1}{\rho g}+\frac{V_2^2-V_1^2}{2g}+z_2-z_1\\\Rightarrow h=\frac{(1.4-0.6)\times 10^5}{800\times 9.81}+\frac{6.67_2^2-3.33^2}{2\times 9.81}+3\\\Rightarrow h=14.896\ m](https://tex.z-dn.net/?f=%5Cfrac%20%7BP_1%7D%7B%5Crho%20g%7D%2B%5Cfrac%7BV_1%5E2%7D%7B2g%7D%2Bz_1%2Bh%3D%5Cfrac%20%7BP_2%7D%7B%5Crho%20g%7D%2B%5Cfrac%7BV_2%5E2%7D%7B2g%7D%2Bz_2%5C%5C%5CRightarrow%20h%3D%5Cfrac%7BP_2-P_1%7D%7B%5Crho%20g%7D%2B%5Cfrac%7BV_2%5E2-V_1%5E2%7D%7B2g%7D%2Bz_2-z_1%5C%5C%5CRightarrow%20h%3D%5Cfrac%7B%281.4-0.6%29%5Ctimes%2010%5E5%7D%7B800%5Ctimes%209.81%7D%2B%5Cfrac%7B6.67_2%5E2-3.33%5E2%7D%7B2%5Ctimes%209.81%7D%2B3%5C%5C%5CRightarrow%20h%3D14.896%5C%20m)
Work done by pump
![W_{p}=\rho gQh\\\Rightarrow W_{p}=800\times 9.81\times 0.2\times 14.896\\\Rightarrow W_{p}=23380.8\ W](https://tex.z-dn.net/?f=W_%7Bp%7D%3D%5Crho%20gQh%5C%5C%5CRightarrow%20W_%7Bp%7D%3D800%5Ctimes%209.81%5Ctimes%200.2%5Ctimes%2014.896%5C%5C%5CRightarrow%20W_%7Bp%7D%3D23380.8%5C%20W)
∴ Power input to the pump 23.3808 kW
Now neglecting kinetic energy
![h=\frac{P_2-P_1}{\rho g}+z_2-z_1\\\Righarrow h=\frac{(1.4-0.6)\times 10^5}{800\times 9.81}+3\\\Righarrow h=13.19\ m\\](https://tex.z-dn.net/?f=h%3D%5Cfrac%7BP_2-P_1%7D%7B%5Crho%20g%7D%2Bz_2-z_1%5C%5C%5CRigharrow%20h%3D%5Cfrac%7B%281.4-0.6%29%5Ctimes%2010%5E5%7D%7B800%5Ctimes%209.81%7D%2B3%5C%5C%5CRigharrow%20h%3D13.19%5C%20m%5C%5C)
Work done by pump
![W_{p}=\rho gQh\\\Rightarrow W_{p}=800\times 9.81\times 0.2\times 13.193\\\Rightarrow W_{p}=20708.8\ W](https://tex.z-dn.net/?f=W_%7Bp%7D%3D%5Crho%20gQh%5C%5C%5CRightarrow%20W_%7Bp%7D%3D800%5Ctimes%209.81%5Ctimes%200.2%5Ctimes%2013.193%5C%5C%5CRightarrow%20W_%7Bp%7D%3D20708.8%5C%20W)
∴ Power input to the pump 20.7088 kW
Answer:
200
Explanation:
A size sheets (also known as letter size) are 8.5 inches by 11 inches.
B size sheets (also known as ledger size) are 11 inches by 17 inches.
One B size sheet is twice as large as a A size sheet. So if you have 100 B size sheets and cut each one in half, you'll get 200 A size sheets.
Answer:
6.99 x 10⁻³ m³ / s
Explanation:
Th e pressure difference at the two ends of the delivery pipe due to atmospheric pressure and water column will cause flow of water.
h = difference in the height of water column at two ends of delivery pipe
6 - 1 = 5 m
Velocity of flow of water
v = √2gh
= √ (2 x 9.8 x 5)
= 9.9 m /s
Volume of water flowing per unit time
velocity x cross sectional area
= 9.9 x 3.14 x .015²
= 6.99 x 10⁻³ m³ / s
Answer:
f(x)=23x−2
Explanation:
still trying to figure that out
Answer: b) False
Explanation: Microscopic energy is the the energy that is based on the molecular level in a particular energy system. Microscopic energy basically comprise with tiny particles like atoms and molecules .The sum of all microscopic form of energy e together make the internal energy .Therefore, the statement given is false because the sum of all the microscopic forms of energy of a system is quantified as internal energy not flow energy.