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Sunny_sXe [5.5K]
3 years ago
13

Given three different locations on Earth's surface, where will the weight of a person be greatest? in New York City, which is ab

out 6369 km from the center of the Earth at the South Pole, which is about 6356 km from the center of the Earth on the Equator line, which is about 6378 km from the center of the Earth the weight is the same at all three locations
Physics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

B. South Pole.

Explanation:

In order to answer this question, we simply have to refer to the laws of the equations of gravitational mechanics.

The equation given by Newton tells us that

F = \frac {Gm_1m_2} {r^2}

In the case where we compare a specific place where the Force of Gravity is greater or lesser, we focus on the term assigned to the Planet's Radius.

In the case of G, m_1, m_2, we understand that they are constant.

We can easily notice that the more the Radius (Height seen from a viewer on the ground), the lower the force will be.

<em>In other words, the smaller the radius in which the measurement is made with respect to the center of the earth, the greater the gravitational force.</em>

In that order of ideas the smallest radio has South Pole, which is about 6356 km from the center of the Earth on the Equator line

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Must all species reproduce in order for the species to survive?
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ANSWER:

the correct answer is D.Yes; without reproduction, once the living organisms died, there would be no offspring to replace them.

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Answer:

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Explanation:

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3 years ago
A car travels north along a straight highway at an average speed of 85 km/h. After driving 2.0 km, the car passes a gas station
jenyasd209 [6]

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3 years ago
you have been called to testify as a as an expert witness in a trial involving a head-on collision Car A weighs 1515 pounds and
GrogVix [38]

Answer:

70.6 mph

Explanation:

Car A mass= 1515 lb

Car B mass=1125 lb  

Speed of car B is 46 miles/h

Distance before locking, d=19.5 ft

Coefficient of kinetic friction is 0.75

Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

Momentum_B=1125*67.4666668 ft/s

Initial momentum of car A is given by

Momentum_A=1515v_a where v_a is velocity of A

Taking East as positive and west as negative then the sum of initial momentum is

1515v_a-(1125*67.4666668 ft/s)

The common velocity is represented as v_c hence after collision, the final momentum is

Momentum_final=(m_a+m_b)v_c=(1515+1125)v_c=2640v_c

From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence

1515v_a-(1125*67.4666668 ft/s)= 2640v_c

The acceleration of two cars a=-\mug=-0.75*32.17=-24.1275 ft/s^{2}

From kinematic equation

v^{2}=u^{2}+2as hence

v^{2}-u^{2}=2as

0^{2}-(v_c)^{2}=2*-24.1275*19.5

v_c=\sqrt{2*24.1275*19.5}=30.67 ft/s

Substituting the value of v_c in equation 1515v_a-(1125*67.4666668 ft/s)= 2640v_c

1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

1515v_a=(1125*67.4666668 ft/s)+2640*30.67

v_a=\frac {156868.8}{1515}=103.5438 ft/s

\frac {103.5438}{1.46667}=70.59787 mph\approx 70.60 mph

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