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Solnce55 [7]
3 years ago
7

If a machine is doing 500 J of work with 75 watts of power, how long did it take to complete its task?

Physics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

time = 6.67secs

Explanation:

power = workdone( energy) / time

therefore :

Time = workdone / power

time = 500 / 75

time = 6.67secs

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A science class puts a balloon containing 1.25 l of air at 101 kpa into a bell jar. using an air pump, the class removes some of
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The first thing you should know in this case is the following definition:
 PV = nRT
 Then, as the temperature is constant, then:
 PV = k
 Then, we have two states:
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 Substituting the values:
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8 0
3 years ago
QUESTION 9
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Answer:

The answer is option a.

Hope this helps

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3 years ago
Which of the following is a common feature among the four inner planets?
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<span>rocky surface

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6 0
2 years ago
A 2-kg box is pushed by a force of 4 N for 2 seconds. It has an initial velocity vo = 2 m/s to the right. NOTE: Since this probl
IRISSAK [1]

Answer:

Kf= 36 J

W(net) = 32 J

Explanation:

Given that

m = 2 kg

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t= 2 s

Initial velocity ,u= 2 m/s

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F= dP/dt

F.t = ΔP

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ΔP = m v  - m u

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By putting the values

4 x 2 = 2 ( v - 2)

8 =  2 ( v - 2)

4 = v - 2

v= 6 m/s

The final kinetic energy Kf

Kf= 1/2 m v²

Kf= 0.5 x 2 x 6²

Kf= 36 J

Initial kinetic energy Ki

Ki = 1/2 m u²

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W(net) = Kf - Ki

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W(net) = 32 J

7 0
2 years ago
An archeologist on a dig finds a fragment of an ancient
marin [14]

Answer:

19792.96488 years

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\tau_{\dfrac{1}{2}} = Half life of carbon-14 atom = 5730 years

Disintegration is given by

\lambda=\dfrac{ln2}{\tau_{\dfrac{1}{2}}}\\\Rightarrow \lambda=\dfrac{ln2}{5730}\\\Rightarrow \lambda=0.00012\ /years

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0.093N_0=N_0e^{-\lambda t}\\\Rightarrow 0.093N_0=N_0e^{-0.00012 t}\\\Rightarrow ln\dfrac{1}{0.093}=0.00012t\\\Rightarrow t=\dfrac{ ln\dfrac{1}{0.093}}{0.00012}\\\Rightarrow t=19792.96488\ years

The age of the basket is 19792.96488 years

4 0
3 years ago
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