The dependant variable is what you measure during the experiment and what is affected in the experiment (this is for question 4) so the answer would be D
I think it is correct......
Answer:
I don't know what to say . just for points
I say B. Why? because the heat will keep on moving in molecules until it reaches same temperature
Answer:
The energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J
Explanation:
Let the charge on the cation be q₁
Also let the charge on the anion be q₂
A cation q₁ with a valence of 1, has a charge of 1 X 1.602×10⁻¹⁹C = 1.602×10⁻¹⁹C
An anion q₂ with a valence of 3, has a charge of 3 X 1.602×10⁻¹⁹C = 4.806 ×10⁻¹⁹C
The distance between the two charges is 7.5nm = 7.5 X10⁻⁹m
Energy of attraction = ![\frac{Kq_1q_2}{r^2}](https://tex.z-dn.net/?f=%5Cfrac%7BKq_1q_2%7D%7Br%5E2%7D)
Where k is coulomb's constant = 8.99 X 10⁹ Nm₂/C₂
Energy of attraction = ![\frac{8.99 X 10^9 (1.602X10^{-19})(4.806 X10^{-19})}{(7.5X10^{-9})^2}](https://tex.z-dn.net/?f=%5Cfrac%7B8.99%20X%2010%5E9%20%281.602X10%5E%7B-19%7D%29%284.806%20X10%5E%7B-19%7D%29%7D%7B%287.5X10%5E%7B-9%7D%29%5E2%7D)
Energy of attraction = 1.231 X 10⁻¹¹ J
Therefore, the energy of attraction between the cation and anion is 1.231 X 10⁻¹¹ J