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Anettt [7]
3 years ago
11

You want to improve your grades so that you make all A's next 6 weeks. List examples of quantitative and qualitative data you sh

ould collect. Suggest at least TWO ways to apply each CT strategy to the problem GIVE EXAMPLES and DETAILS!!!!!!!! You DO NOT simply define Plz help I will give brainliest
Engineering
1 answer:
Naddika [18.5K]3 years ago
6 0

Explanation:

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3fभथठभदाफमदखज्ञफादफज्ञादफज्ञिलफ इऋबिअऋब

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Instead of running blood through a single straight vessel for a distance of 2 mm, one mammalian species uses an array of 100 tin
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Solution:

Given that :

Volume flow is, $Q_1 = 1000 \ mm^3/s$

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Therefore, the equation of a single straight vessel is given by

$F_{f_1}=\frac{8flQ_1^2}{\pi^2gd_1^5}$    ......................(i)

So there are 100 similar parallel pipes of the same cross section. Therefore, the equation for the area is

$\frac{\pi d_1^2}{4}=1000 \times\frac{\pi d_2^2}{4} $

or $d_1=10 \ d_2$

Now for parallel pipes

$H_{f_2}= (H_{f_2})_1= (H_{f_2})_2= .... = = (H_{f_2})_{10}=\frac{8flQ_2^2}{\pi^2 gd_2^5}$  ...........(ii)

Solving the equations (i) and (ii),

$\frac{H_{f_1}}{H_{f_2}}=\frac{\frac{8flQ_1^2}{\pi^2 gd_1^5}}{\frac{8flQ_2^2}{\pi^2 gd_2^5}}$

       $=\frac{Q_1^2}{Q_2^2}\times \frac{d_2^5}{d_1^5}$

       $=\frac{(1000)^2}{(10)^2}\times \frac{d_2^5}{(10d_2)^5}$

       $=\frac{10^6}{10^7}$

Therefore,

$\frac{H_{f_1}}{H_{f_2}}=\frac{1}{10}$

or $H_{f_2}=10 \ H_{f_1}$

Thus the answer is option A). 10

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