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Radda [10]
3 years ago
7

Helps please people

Physics
1 answer:
serg [7]3 years ago
7 0
1. The iris regulates the amount of light entering the eye
2. The retina receives and organises visual information
3. The lens refracts light rays in a camera
You might be interested in
When a 40-n force, parallel to the incline and directed up the incline, is applied to a crate on a frictionless incline that is
Genrish500 [490]
<span>F= ma force is directed on the working surface so 40 = m x 2 hence m must be 20 units needed are probably kg</span>
8 0
3 years ago
Liquid water at 120 kPa enters a 7-kW pump where its pressure is raised to 5.6 MPa. If the elevation difference between the exit
ziro4ka [17]

Answer:

The answer is given below

Explanation:

Things provided in the statement:

Pressure <em>P1</em> = 120 kPa and <em>P2</em> = 5.6 MP or 5600 kPa

Power, <em>W</em> = 7 kW

Elevation difference = ∆z = 10 m

Mass of flow = m˙

So potential energy changes may be significant

Specific volume of water V= 0.001 m³/kg

Now putting the values in the formula

Power, <em>W </em>= m˙  x V (<em>P1 - P2</em>) + m˙ x g x ∆z

             7 = m˙  x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)

             7 = m˙ x 5.48 + m˙ x 0.098

             7 = m ˙x 5.38

            m˙ = 7/5.38

          So mass flow m˙  =  1.301 kJ/s

8 0
3 years ago
A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is do
Alborosie

1. B. T

The period of a simple pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}} (1)

where

L is the length of the pendulum

g is the gravitational acceleration

From the formula, we notice that the period of the pendulum does not depend on the mass of the bob. Therefore, when the bob's mass is doubled, the period does not change.

2. C: sqrt(6)*T

In this case, the pendulum is brought to the moon, where the gravitational acceleration is

g'=\frac{g}{6}

If we substitute this value into the equation for the period (1), we find the new period of the pendulum:

T'=2\pi \sqrt{\frac{L}{g'}}=2\pi \sqrt{\frac{L}{(g/6)}}=\sqrt{6}(2\pi \sqrt{\frac{L}{g}})=\sqrt{6} T

3. B: It will no longer oscillate because there is no gravity in space

Explanation:

The motion (oscillation) of the pendulum is caused by the force of gravity, which "pulls" the bob towards the equilibrium position. If there is no gravity, then there is no force acting on the bob, therefore the pendulum can no longer oscillate.

So, the correct answer is

B: It will no longer oscillate because there is no gravity in space

4 0
4 years ago
Read 2 more answers
Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con
Vitek1552 [10]

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

Stopping time = 11hrs 30min

Speed  = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

 Speed = \frac{distance}{time}

 Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

  Input the parameters:

  Distance = 910km/hr x 4.5hrs = 4095km

learn more:

Speed brainly.com/question/10048445

#learnwithBrainly

6 0
3 years ago
A simple pendulum 50 oscillations 22.3s find its period​
Harman [31]

Answer:

22.3s / 50 =0.446s

Explanation:

6 0
3 years ago
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