Question

An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magnitude of the velocity?

Answer 1

Answer:

$v=10^5\ m/s$

Explanation:

Given that,

Magnetic force acting on an electron, $F=12.8\times 10^{-19}\ N$

The magnitude of the magnetic field,$B=8\times 10^{-5}\ T$

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

$F=qvB$

Where

v is the velocity

So,

$v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s$

So, the magnitude of velocity is$10^5\ m/s$.