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2 years ago

How many nitrate ions are in 2 mol of iron (II) nitrate

Chemistry

1 answer:

Allisa [31]2 years ago

7 0

Answer:

Two

Explanation:

Nitrate has a charge of negative 1 and the Iron (II) tells us the iron in that formula has a charge of +2, so in order for the iron to have to equal positive two, there has to be two negative. Since on nitrate ion is -1, you need two to make -2.

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3 years ago

What is the molarity of 0.26 mol of H2SO4 dissolved in 0.3 L of solution? *

irina1246 [14]

Answer:

Explanation:

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3 years ago

Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying

PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? ( $K_a$ for HF is $6.8\times 10^{-4}$ .)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = $K_a=6.8\times 10^{-4}$

$HF\rightleftharpoons H^++F^-$

Initially

c 0 0

At equilibrium :

(c-x) x x

The expression of disassociation constant is given as:

$K_a=\frac{[H^+][F^-]}{[HF]}$

$K_a=\frac{x\times x}{(c-x)}$

$6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}$

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

$[H^+]=x=0.01346 M$

The pH of the solution is ;

$pH=-\log[H^+]=-\log[0.01346 M]=1.87$

The pH of an 0.280 M HF solution is 1.87.

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3 years ago

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3 years ago

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Answer:

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<h3>C. The balloon with CH4 has the same moles of gas molecules as the balloon with H2</h3>

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3 years ago