C. All the energy stored in the battery had been transformed.
B) The velocity of the car reduced from 50k/m over one min.
Answer:
The reaction can produce 287 grams of iron(II) carbonate
Explanation:
To solve this question we must find the moles of iron(II) chloride that react. Using the chemical equation we can find the moles of iron(II) carbonate and its mass -Molar mass FeCO3: 115.854g/mol-
<em>Moles FeCl2:</em>
1.24L * (2.00mol / L) = 2.48 moles FeCl2
As 1 mol FeCl2 produce 1 mol FeCO3, the moles of FeCO3 = 2.48 moles
<em>Mass FeCO3:</em>
2.48mol * (115.854g / mol) =
<h3>The reaction can produce 287 grams of iron(II) carbonate</h3>
"equal to"
1=1
1 is equal to 1
Is this what you mean?
Answer:
= 160 mL
Explanation:
The equation for the reaction is;
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O
Moles of Ca(OH)2 = 0.080 L x 5.00^-3 M
= 0.0004 moles
From the reaction; 2 moles of HNO3 reacts with 1 mole of Ca(OH)2
Thus; moles of HNO3 = 0.0004 Moles × 2
= 0.0008 moles
Volume = moles/ molarity
Therefore; volume of HNO3= 0.0008 Moles/ 5 × 10^-3 M
<u>= 0.16 L or 160 mL</u>
