Answer:
hello your question is incomplete attached below is the missing part
answer : short period oscillations frequency = 0.063 rad / sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Explanation:
first we have to state the general form of the equation
= ![( S^2 + 2\alpha _{p} w_{np} S + w^{2} _{np} ) (S^{2} + 2\alpha _{s} w_{ns}S + w^{2} _{ns} ) = 0](https://tex.z-dn.net/?f=%28%20S%5E2%20%2B%202%5Calpha%20_%7Bp%7D%20w_%7Bnp%7D%20S%20%2B%20w%5E%7B2%7D%20_%7Bnp%7D%20%29%20%28S%5E%7B2%7D%20%2B%202%5Calpha%20_%7Bs%7D%20w_%7Bns%7DS%20%2B%20w%5E%7B2%7D%20_%7Bns%7D%20%20%29%20%3D%200)
where :
![w_{np} = Natural frequency of plugiod oscillation](https://tex.z-dn.net/?f=w_%7Bnp%7D%20%20%3D%20Natural%20frequency%20of%20plugiod%20oscillation)
![\alpha _{p} = damping ratio of plugiod oscilations](https://tex.z-dn.net/?f=%5Calpha%20_%7Bp%7D%20%3D%20damping%20ratio%20of%20plugiod%20%20oscilations)
comparing the general form with the given equation
= 18.2329
![w^{2} _{ns} = 0.003969](https://tex.z-dn.net/?f=w%5E%7B2%7D%20_%7Bns%7D%20%3D%200.003969)
hence the short period oscillation frequency (
) = 0.063 rad/sec
phugoid oscillations natural frequency (
) = 4.27 rad/sec
Answer:The rate of ejection of photoelectrons will increase
Explanation:
If the frequency of incident monochromatic light is held constant and its intensity is increased, the rate of ejection of photoelectrons from the metal surface increases with increase in intensity of the monochromatic light. More current flows due to more ejection of photoelectrons.
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert<span> small force on the wall The </span>pressure exerted<span> by the </span>gas<span> is due to the sum of all these collision forces.The more particles that hit the walls, the higher the </span>pressure<span>.</span>
Answer:
The material with higher modulus will stretch less than
The material with lower modulus
Explanation:
A material with a higher modulus is stiffer and has better resistance to deformation. The modulus is defined as the force per unit area required to produce a deformation or in other words the ratio of stress to strain.
E= stress/stain
Hooks law states that provided the elastic limit is not exceeded the extension e of a spring is directly proportional to the load or force attached
F=ke
Where k is the constant which gives the measure of the spring under tension
From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.
<h3>What is velocity?</h3>
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity.
it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.
Given data:
V(Final velocity)=? (m/sec)
h(height)= 6.0 m
u(Initial velocity)=0 m/sec
g(gravitational acceleration)=9.81 m/s²
Newton's third equation of motion:
![\rm v_y^2 = u_y^2+ 2gh \\\\\rm v_y^2 = 0+ 2gh\\\\\ v_y= \sqrt{2\times 9.81 \ (m/s^2)\times 6.0 (m)} \\\\ v_y=10.849 \ m/sec](https://tex.z-dn.net/?f=%5Crm%20v_y%5E2%20%3D%20u_y%5E2%2B%202gh%20%5C%5C%5C%5C%5Crm%20v_y%5E2%20%3D%200%2B%202gh%5C%5C%5C%5C%5C%20%20v_y%3D%20%5Csqrt%7B2%5Ctimes%209.81%20%5C%20%28m%2Fs%5E2%29%5Ctimes%206.0%20%28m%29%7D%20%5C%5C%5C%5C%20v_y%3D10.849%20%5C%20m%2Fsec)
Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972
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