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3 years ago

What is the common property of the elements pinctogen

Physics

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

The pnictogens consist of two non-metals, two metalloids, one metal, and one element with unknown chemical properties. All the elements in the group are solids at room temperature, except for nitrogen which is gaseous at room temperature.

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A rollercoaster car has 2500 J of potential energy and 160 J of

Mrrafil [7]

Answer:

xaubUajnaai ajn AJ au aun a

Explanation:

ahayba uabah an aj

6 0

3 years ago

A solenoid of radius 2.0 mm contains 100 turns of wire uniformly distributed over a length of 5.0 cm. It is located in air and c

tankabanditka [31]

Answer:

The magnetic field strength inside the solenoid is $5.026\times10^{-3}\ T$ .

Explanation:

Given that,

Radius = 2.0 mm

Length = 5.0 cm

Current = 2.0 A

Number of turns = 100

(a). We need to calculate the magnetic field strength inside the solenoid

Using formula of the magnetic field strength

Using Ampere's Law

$B=\dfrac{\mu_{0}NI}{l}$

Where, N = Number of turns

I = current

l = length

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times100\times2.0}{5.0\times10^{-2}}$

$B=0.005026=5.026\times10^{-3}\ T$

(b). We draw the diagram

Hence, The magnetic field strength inside the solenoid is $5.026\times10^{-3}\ T$ .

4 0

3 years ago

A large truck is moving 22.0 m/s. If it’s momentum is 125,000 kg • m/s, what is the trucks mass

strojnjashka [21]

Answer:

p = mv

m = p/v = 125000/22 = 5682 kg

Explanation:

Direct application of the momentum equation

p = mv

where,

p: momentum

m: mass

v: object velocity

steps:

-------

1) check for units consistency ( SI or Imperial)

2) separate the variable you are looking for.

3) DONE! :DD

6 0

3 years ago

A disk-shaped grindstone of mass 3.0 kg and radius 8.0 cm is spinning at 600 rev/min. After the power is shut off, a man continu

kolbaska11 [484]

Answer:

τ=0.060 N.m

Explanation:

By kinematics:

$\omega f = \omega o-\alpha*t$

Solving for α:

$\alpha=\frac{\omega o-\omega f}{t}$

where ωo = 600*2*π/60; ωf = 0; t=10s

$\alpha=6.283rad/s^2$

The sum of torque is:

$\tau=I*\alpha$

$\tau=M*R^2/2*\alpha$

$\tau=0.060 N.m$

8 0

3 years ago

A constant force of magnitude F acts on an object of mass 0.04kg initially at rest at a point O. If the speed of the object when

vampirchik [111]

Answer:

F = 100 Newtons

Explanation:

F = ?

m = 0.04kg

u = 0m/s ==> u is just an abbreviation for initial velocity, it is conventional.

s = 50m ==> s is just an abbreviation for distance, it is conventional.

v = 500m/s ==> v is just an abbreviation for final velocity, it is conventional.

$v^{2} = u^{2} + 2as\\\\=> a = \frac{v^{2} - u^{2}}{2s}\\a = \frac{500^{2} }{2*50}\\a = 2500ms^{-2}$

Then F = ma = 0.04 x 2500 = 100N

5 0

3 years ago