Steve and Meg are doing an experiment where they need to make 37 grams of Fe2O3. How many grams of Fe would they need ?
1 answer:
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The Molarity of the solution is given by:
--- (A)
But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.
Molecular weight of NaCl = 58.44 grams/mole.
So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl
Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre
The correct answer is: 0.741 moles/litre = Molarity
But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.
Molecular weight of NaCl = 58.44 grams/mole.
So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl
Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre
The correct answer is: 0.741 moles/litre = Molarity