1. True/False The Pressure Relief valve maintains the minimum pressure in the hydraulic circuit

Estimate the endurance strength, Se, of a 37.5-mm- diameter rod of AISI 1040 steel having a machined finish and heat-treated to

7nadin3 [17]

Answer:

endurance length is 236.64 MPa

Explanation:

data given:

d = 37.5 mm

Sut = 760MPa

endurance limit is

Se = 0.5 Sut

= 0.5*760 = 380 MPa

surface factor is

Ka = a*Sut^b

where

Sut is ultimate strength

for AISI 1040 STEEL

a = 4.51, b = -0.265

Ka = 4.51*380^{-0.265}

Ka = 0.93

size factor is given as

Kb =1.29 d^{-0.17}

Kb = 0.669

Se = Sut *Ka*Kb

= 380*0.669*0.93

Se = 236.64 MPa

therefore endurance length is 236.64 MPa

4 0

3 years ago

What is a system that performs different functions according to a fixed schedule?

geniusboy [140]

I'm pretty sure your answer is B, because Sequential Control operates during order like a schedule

Sequential Control=A control system in which the individual steps are processed in a predetermined order, progression from one sequence step to the next being dependent on defined conditions being satisfied.

Tell me if I'm incorrect but, Hope this helps!

4 0

3 years ago

Read 2 more answers

Can anyone explain how a Halbek Device works

dedylja [7]

Answer:

The Halbek Device can be used effectively on some weapons with practice and certain loadouts. ... This tends to help high-damage weapons or weapons with high multipliers

8 0

2 years ago

Read 2 more answers

An equal-tangent vertical curve is to be constructed between grades of -2% (initial) and 1% (final). The PVI is at station 110 0

Mila [183]

Answer:

The curve length (L) will be = 1218 ft

The elevations and stations for PVC and PVI

a. station of PVC = 103 + 91.00

b. station of PVI = 116 + 09.00

c. elevation of PVC = 432.18ft

d. elevation of PVI = 426.09ft

Explanation:

First calculate for the length (L)

To calculate the length, use the formula of "elevation at any point".

where, elevation at any point = 424.5.

and ∴ PVC Elevation = (420 + 0.01L)

Then, calculate for Station of PVC and PVI and elevation of PVC and PVI

4 0

3 years ago

A specimen of a 4340-steel alloy with a plane strain fracture toughness of 54.8 MPa sqrt(m) (50 ksi sqrt(in.)) is exposed to a s

Lunna [17]

Answer:

critical stress $\sigma _c$ = 1382.67 MPa

Explanation:

given data

plane strain fracture toughness = 54.8 MP

length of surface creak = 0.5 mm

we take here

parameter Y = 1.0

solution

we apply critical stress formula that is

critical stress $\sigma _c$ = $\frac{K}{Y\sqrt{\pi \times a} }$ .............................1

here K is design stress plane strain fracture toughness and a is length of surface creak so put all these value in equation 1

critical stress $\sigma _c$ = $\frac{54.8 \times 10^6}{1 \sqrt{\pi \times 5 \times 106{-4}}}$

solve it we get

critical stress = 1382.67 MPa

As exposed stress 1030 MPa is less than critical stress 1382 MPa

so that fracture will not be occur here

7 0

3 years ago

1. True/False The Pressure Relief valve maintains the minimum pressure in the hydraulic circuit​

1. True/False The Pressure Relief valve maintains the minimum pressure in the hydraulic circuit