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Harrizon [31]
3 years ago
13

1. True/False The Pressure Relief valve maintains the minimum pressure in the hydraulic circuit​

Engineering
1 answer:
elena55 [62]3 years ago
3 0
Yeah it’s true. Good luck!!
You might be interested in
1. (16 points) True or False, one point each, Write down F (false) or T (true). ___ (01) In a mechanical design, it is recommend
nikitadnepr [17]

Answer:

True

Explanation:

I looked it up

3 0
4 years ago
*13–52. A girl, having a mass of 15 kg, sits motionless relative to the surface of a horizontal platform at a distance of r = 5
Dennis_Churaev [7]

Answer:

  w = 0.626 rad / s, v = 3.13 m/s

Explanation:

For this exercise let's use Newton's second law

        F = m a

Where the force is a friction force and the acceleration is centripetal,

      a = v² / r = w² r

The formula for friction force

     fr = μ N

  In a free body diagram

       N- W = 0

      W = N

The frictiμon outside goes from zero to the maximum value, let's calculate the speed for the maximum value of the friction force, replace

       μ m g = m w² r

       w = √ μ g / r

Let's calculate

     w = √(0.2 9.8 / 5)

     w = 0.626 rad / s

angular and linear velocity are related

      v = w r

      v = 0.626 5

      v = 3.13 m/s

6 0
3 years ago
The enthalpy of the water entering an actual pump is 500 kJ/kg and the enthalpy of the water leaving it is 550 kJ/kg. The pump h
n200080 [17]

Answer:500,551.02

Explanation:

Given

Initial enthaly of pump \left ( h_1\right )=500KJ/kg

Final  enthaly of pump \left ( h_2\right )=550KJ/kg

Final  enthaly of pump when efficiency is 100%=h_2^{'}

Now pump efficiency is 98%

\eta=\frac{h_2-h_1}{h_2^{'}-h_1}

0.98=\frac{550-500}{h_2-500}

h_2=551.02KJ/kg

therefore initial and final enthalpy of pump for 100 % efficiency

initial=500KJ/kg

Final=551.02KJ/kg

3 0
3 years ago
(a) For BCC iron, calculate the diameter of the minimum space available in an octahedral site at the center of the (010) plane,
Romashka-Z-Leto [24]

Answer:

a) diameter available = 0.0384 nm

b)The space  is smaller than the carbon atom which has a  radius of  0.077 nm and this simply means that the carbon atom will not conquer these sites

Explanation:

For BCC iron

From Appendix B given,select the lattice parameter ( a ) as = 0.2866 nm

The BCC iron has 4 atomic radii and therefore the body diagonal length = a(3)^\frac{1}{2}

expressing the atomic radius of the BCC iron

4r = a(3)^\frac{1}{2}

insert the value of (a) from appendix B which is = 0.2866 nm

4r = 0.2866 nm (3)^\frac{1}{2}

therefore  r =  0.4964 nm / 4 = 0.1241 nm

Refer again to appendix C given select the atomic radius of the BCC iron as = 0.1241 nm   assuming the atomic radius of the iron are the same

then the radius ratio = 0.62

Refer to the Figure 3.2 given, the amount of space required for an interstitial at the BCC position is between the atoms at the FCC position and also in this space there are two atoms that are equal to a radius of 0.2482 nm

The diameter of the minimum space available

d_{a} = a - r_{a}

r_{a}  = atomic radii = 0.2482 nm

a = 0.2666 nm

therefore

d_{a} = 0.2866 nm - 0.2482 nm = 0.0384 nm

comparing this to the diameter of a carbon atom

The space  is smaller than the carbon atom which has a  radius of  0.077 nm and this simply means that the carbon atom will not conquer these sites

7 0
3 years ago
What is vapier calliper​
SIZIF [17.4K]

Answer:

A calliper is a device used to measure the dimensions of an object.

Many types of calipers permit reading out a measurement on a ruled scale, a dial, or a digital display. Some calipers can be as simple as a compass with inward or outward-facing points, but no scale.

I'm not sure what a "Vapier" Calliper is, but I assume it's about the same thing.

4 0
2 years ago
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