The titration of an acid (H2A) with LiOH solution generates the following titration curve. What are the main components (more th
an half of the initial amount of H2A, besides H2O) at equivalence point 1 (EP1) and equivalence point 2 (EP2)?
Main Components at EP1 Main Components at EP2
A H2A and OH− A2− and OH−
B HA− and Li+ A2− and Li+
C HA− and OH− HA− and Li+
D H2A and Li+ HA− and OH−
Main Components at EP1 Main Components at EP2
A H2A and OH− A2− and OH−
B HA− and Li+ A2− and Li+
C HA− and OH− HA− and Li+
D H2A and Li+ HA− and OH−
1 answer:
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Answer:
Plausible structure has been given below
Explanation:
- Molar mass of
is 44 g/mol and molar mass of
is 18 g/mol
- Number of mole = (mass/molar mass)
4.04 g of =
= 0.0918 moles of
1 mol of contains 1 mol of C atom
So, 0.0918 moles of contains 0.0918 moles of C atom
1.24 g of =
= 0.0689 moles of
1 mol of contain 2 moles of H atom
So, 0.0689 moles of contain
of
or 0.138 moles of
Moles of C : moles of H = 0.0918 : 0.138 = 2 : 3
Empirical formula of hydrocarbon is
So, molecular formula of one of it's analog is
Plausible structure of has been given below.
Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 3.16 L of chlorine were consumed at STP.
Be sure your answer has the correct number of significant digits.
Answer: Thus volume of carbon tetrachloride that would be produced is 0.788 L
Explanation:
According to ideal gas equation:
P = pressure of gas = 1 atm (at STP)
V = Volume of gas = 3.16 L
n = number of moles = ?
R = gas constant =
T =temperature =
According to stoichiometry:
4 moles of chlorine produces = 1 mole of carbon tetrachloride
Thus 0.141 moles of methane produces = moles of carbon tetrachloride
volume of carbon tetrachloride =
Thus volume of carbon tetrachloride that would be produced is 0.788 L