A - 10 watts
D - 13-1/3 watts
B - 20 watts
C - 40 watts
Power = (work done) / (time to do it)
Answer:
total momentum = 8.42 kgm/s
velocity of the first cart is 3.660 m/s
Explanation:
Given data
mass m1 = 2.3 kg
mass m2 = 1.5 kg
final velocity V2 = 4.9 m/s
final velocity V3 = - 1.9 m/s
to find out
total momentum and velocity of the first cart
solution
we know mass and final velocty
and initial velocity of second cart V1 = 0
so now we can calculate total momentum that is m1 v2 + m2 v2
total momentum = 2.3 ×4.9 + 1.5 ×(-1.9)
total momentum = 8.42 kgm/s
and
conservation of momentum is
m1 V + m2 v1 = m1 v2 + m2 v3
put all value and find V
2.3 V + 1.5 ( 0) = 2.3 ( 4.9 ) + 1.5 ( -1.9)
V = 8.42 / 2.3
V = 3.660 m/s
so velocity of the first cart is 3.660 m/s
Answer:
60 J
Explanation:
KE = ½ mv²
KE = ½ (0.3 kg) (20 m/s)²
KE = 60 J
Answer: Varying amounts of the Moon's lit surface being visible from Earth.
Explanation:
Phases of the moon can be defined as the different shapes of the moon visible from the Earth. This happens because sun lits up the face of moon and due to different position of moon in the orbit around earth, varying portion of the lit surface of the moon is visible from Earth. Refer to the diagram below:
Answer:
The answer to your question is distance between these electrons
= 1.386 x 10⁻¹⁴ m
Explanation:
Data
Force = F = 1.2 N
distance = d = ?
charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C
K = 8.987 x 10⁹ Nm²/C²
Formula
-To solve this problem use the Coulomb's equation
F = kq₁q₂ / r²
-Solve for r²
r² = kq₁q₂ / F
-Substitution
r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2
- Simplification
r² = 2.306 x 10⁻²⁸ / 1.2
r² = 1.922 x 10⁻²⁸
-Result
r = 1.386 x 10⁻¹⁴ m