Answer:
I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5
Explanation:
Use the m*g*h=1/2*k*x^2 equation
96*9.81*60=1/2*k*2^2
5650.56=2k
5650.56/2=2825.28N/m
1) 0.0011 rad/s
2) 7667 m/s
Explanation:
1)
The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

where
is the angular displacement of the object
t is the time elapsed
is the angular velocity
In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is
rad
And the time taken is

Therefore, the angular velocity of the telescope is

2)
For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

where
v is the linear velocity
is the angular velocity
r is the radius of the circular orbit
In this problem:
is the angular velocity of the Hubble telescope
The telescope is at an altitude of
h = 600 km
over the Earth's surface, which has a radius of
R = 6370 km
So the actual radius of the Hubble's orbit is

Therefore, the linear velocity of the telescope is:

Explanation:
In the parallel combination, the equivalent resistance is given by :

4. When three 150 ohms resistors are connected in parallel, the equivalent is given by :

5. Three resistors of 20 ohms, 40 ohms and 100 ohms are connected in parallel, So,

Hence, this is the required solution.
Answer:
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Explanation:
From the question we are told that:
The Electric field of strength direction =Right
The Velocity of The First Electron=V_0
The Velocity of The Second Electron=V_0
Therefore

Generally, the equation for the Horizontal Displacement of electron is mathematically given by

Where
Acceleration is given as

And
Time

Therefore horizontal displacement towards the left is

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Answer:
D thermal energy moves from the marshmallow to your fingers as you touch the marshmallow
Explanation:
Conduction is the movement of thermal energy without the actual movement of the particles of a body. They particles only collide with each other and transfer energy in the process while maintaining their mean positions.