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Nady [450]
4 years ago
11

A car traveled at a constant velocity of 70 mph from noon to 2:00 pm. At 3:00 pm the velocity of the car was 80 mph; and finally

at 4:30 pm the velocity of the car was 40 mph.
Which statement accurately describes the acceleration of the car?
Physics
1 answer:
Paha777 [63]4 years ago
6 0

Answer:

Not sure which statements were give to you for this question, but the vehicle's acceleration from noon to 2:00 PM was <em>zero</em>, the vehicle had a <em>positive</em> acceleration between 2:00 pm and 3:00 pm, and the vehicle had a <em>negative</em> acceleration at 4:30 PM.

Explanation:

From 12:00 PM to 2:00 PM, the vehicle traveled at a constant velocity of 70 MPH, meaning there wasn't any change to the speed. The velocity <em>remained the same</em>. An hour later, the velocity of the vehicle <em>increased</em> to 80 MPH, and finally at 4:30 PM, the velocity of the car <em>decreased </em>and was at 40 MPH.

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A truck on a straight road starts from rest and accelerates at 1.4 m/s 2 until it reaches a speed of 22 m/s. Then the truck trav
Zolol [24]

Answer:

42.11 sec

Explanation:

In first part : The truck start from the rest that is u = 0 m/sec

Acceleration is given as a=1.4m/sec^2

It reaches to a velocity of 22 m/sec so v=22 m/sec

Now according to first law of motion v=u+at

22=0+1.4\times t

t=15.71sec

In second part : The truck maintain a constant speed for 22 sec

In third  part : The truck takes an additional 4.4 sec for stopping

So total time in which the truck is in motion =15.71+22+4.4=42.11 sec

3 0
4 years ago
A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volume is occupied by w
rjkz [21]

Answer:

(a) Volume of the tank is 6.47\times 10^{- 3}\ m^{3}

(b) Temperature is 371^{\circ}C

Pressure is 21.3 kPa

(c) The change in internal energy is 1373.54 kJ/kg

Solution:

As per the question:

Mass of liquid in the tank, m = 1.4 kg

Temperature, T = 200^{\circ}C

Volume occupied by water, V = 25%V_{t} = 0.25V_{t}

Volume occupied by air, V' = 75%V_{t}

where

V_{t} = Volume of tank

Now,

(a) In order to calculate the volume of the tank, we make use of the steam table for specific volume at  as given temperature:

At 200^{\circ}C, the specific volume, v = 0.001157m^{3}/kg

At 200^{\circ}C, the internal energy, u = 850.46 kJ/kg

Now,  Volume of water, V = mv = 1.4\times 0.001157 = 1.62\times 10^{- 3} m^{3}

Thus

V = 0.25V_{t}

V_{t} = \frac{1.62\times 10^{- 3}}{0.25} = 6.47\times 10^{- 3}\ m^{3}

(b) For the final temperature and pressure, we calculate the specific volume, v' and then find the corresponding temperature and pressure from the steam table:

v' = \frac{V_{t}}{m} = \frac{6.47\times 10^{- 3}}{1.4} = 4.63\times 10^{- 3}\ m^{3}/kg

The corresponding temperature to this specific volume, T' = 371^{\circ}C

The corresponding pressure to this specific volume, P' = 21.3 kPa

The corresponding internal energy to this specific volume, u' = 2224 kJ/kg

(c) The change in the internal energy of water is given by:

\Delta U = u' - u = 2224 - 850.46 = 1373.54 kJ/kg

3 0
3 years ago
A thermally isolated system consists of a hot piece of aluminum and a cold piece of copper. The aluminum and the copper are in t
Marrrta [24]

Answer:

the amount of heat that gets through both the wires will be same.

Explanation:

By the Fourier's law of conduction we have:

\dot{Q}=k.A.\frac{dT}{dx}

where:

\dot{Q}= rate of heat transfer

k = thermal conductivity of the material

A = area of the material

dT = temperature difference across the length dx

According to the question, the system to be analysed is isolated from the surrounding.

Until the thermal equilibrium is established between aluminium and copper wires the amount of heat that gets through both the wires will be same.

<em>But the rate of heat transfer through the aluminium will be greater as it has double the thermal conductivity of copper.</em>

8 0
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barxatty [35]
52.1-4.184=47.916 You then either add or subtract this from 68.6 the first temperature of the metal. This will give you your total.
5 0
3 years ago
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Which type of force can be used to kick a soccer ball?
Airida [17]

Answer:

The answer is Friction.

Hope this helps :)

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6 0
2 years ago
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