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Nady [450]
4 years ago
11

A car traveled at a constant velocity of 70 mph from noon to 2:00 pm. At 3:00 pm the velocity of the car was 80 mph; and finally

at 4:30 pm the velocity of the car was 40 mph.
Which statement accurately describes the acceleration of the car?
Physics
1 answer:
Paha777 [63]4 years ago
6 0

Answer:

Not sure which statements were give to you for this question, but the vehicle's acceleration from noon to 2:00 PM was <em>zero</em>, the vehicle had a <em>positive</em> acceleration between 2:00 pm and 3:00 pm, and the vehicle had a <em>negative</em> acceleration at 4:30 PM.

Explanation:

From 12:00 PM to 2:00 PM, the vehicle traveled at a constant velocity of 70 MPH, meaning there wasn't any change to the speed. The velocity <em>remained the same</em>. An hour later, the velocity of the vehicle <em>increased</em> to 80 MPH, and finally at 4:30 PM, the velocity of the car <em>decreased </em>and was at 40 MPH.

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10. Rank the following in terms of increasing power. A. Doing 100 J of work in 10 seconds. B. Doing 100 J of work in 5 seconds.
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A - 10 watts
D - 13-1/3 watts
B - 20 watts
C - 40 watts

Power = (work done) / (time to do it)
3 0
3 years ago
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A 2.3 kg cart is rolling across a frictionless, horizontal track towards a 1.5 kg cart that is initially held at rest. The carts
Inga [223]

Answer:

total momentum = 8.42 kgm/s

velocity of the first cart is 3.660 m/s

Explanation:

Given data

mass m1 = 2.3 kg

mass m2 = 1.5 kg

final velocity V2 = 4.9 m/s

final velocity V3 = - 1.9 m/s

to find out

total momentum  and velocity of the first cart

solution

we know mass and final velocty

and initial velocity of second cart V1 = 0

so now we can calculate total momentum that is m1 v2 + m2 v2

total momentum =  2.3 ×4.9 + 1.5 ×(-1.9)

total momentum = 8.42 kgm/s

and

conservation of momentum  is

m1 V + m2 v1  = m1 v2  + m2 v3

put all value and find V

2.3 V + 1.5 ( 0) = 2.3 ( 4.9 ) + 1.5 ( -1.9)

V = 8.42 / 2.3

V = 3.660 m/s

so velocity of the first cart is 3.660 m/s

8 0
4 years ago
A 0.3-kg ball has the velocity of 20 m/s. what is the kinetic energy of the ball?
snow_tiger [21]

Answer:

60 J

Explanation:

KE = ½ mv²

KE = ½ (0.3 kg) (20 m/s)²

KE = 60 J

7 0
3 years ago
Which of the following contributes to the phases of the Moon as seen from Earth?
balandron [24]

Answer: Varying amounts of the Moon's lit surface being visible from Earth.

Explanation:

Phases of the moon can be defined as the different shapes of the moon visible from the Earth. This happens because sun lits up the face of moon and due to different position of moon in the orbit around earth, varying portion of the lit surface of the moon is visible from Earth. Refer to the diagram below:            

4 0
3 years ago
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Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19
aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

                                                   = 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

  F = kq₁q₂ / r²

-Solve for r²

  r² = kq₁q₂ / F

-Substitution

  r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

  r² = 2.306 x 10⁻²⁸ / 1.2

  r² = 1.922 x 10⁻²⁸

-Result

  r = 1.386 x 10⁻¹⁴ m

7 0
4 years ago
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