Answer:
The result is a vector perpendicular to the xy plane: 23.38 k
Explanation:
The cross product of two vectors r and s is defined only in three-dimensional space and is denoted by r × s. The cross product is defined by the formula:
r × s =║r║·║s║· Sin θ· n
where θ is the angle between r and s in the plane containing them, ‖r‖ and ‖s‖ are the magnitudes of vectors r and s, and n is a unit vector perpendicular to the plane containing a and b in the direction given by the right-hand rule.
So, the result is:
r × s = 4.40 * 7.45 * Sin (134.5°) k = 23.38 k
Answer:
The initial velocity is 12.34[m/s]
Explanation:
To understand this problem, let's draw a sketch of what is happening. In the attached image we can fin de sketch.
According to the equations of uniform movement accelerated we have to express them in the two components x and y.
In this problem we will analyze first the movement in the y axis and its equation to obtain the velocity in the initial point (o) and then with the angle of 33° respect to the horizontal we can find the main velocity.
In the previous equation we have the negative term - (2*a*y), the reason for the negative sign is because gravity is the acceleration that is acting downwards.
Therefore:
Now with the velocity in the y component, we can calculate the main vector of the velocity.
The main topic to understand in this problem is that when the height is maximum the velocity will be zero in the y component, therefore Vy=0 and we can simplify the problem.
Answer: 20 m³
Explanation:
1) Data:
Tanker:
Vt = 2.5 × 10³ m³
Dt = 8 × 10³ kg / m³
Sea water:
Vs = ?
Ds = 1 × 10³ kg / m³
2) Physical principles and formulas
Buoyancy: weight of the object equals the weight of the water displaced (or pushed away) by the object.
Weight of water = Weight of tanker
weight = mass × g ..... g = acceleration due to gravity ≈ constant
density = mass / volume ⇒ mass = density × volume
3) Solution
Weight of water = Weight of tanker
Ds × Vs × g = Dt × Vt × g
1×10³ kg/m³ × Vs × g = 2.5 × 10³ m³ × 8 × 10³ kg / m³ × g
⇒ Vs = 20 × 10⁶ kg / ( 1 × 10³ kg/m³) = 20 m³
Answer: 20 m³
The principle of operation of a pressurized garden sprayer is as follows;
A pressurized garden sprayer is a chamber which is filled with a liquid which can be a lubricant, paint or chemical, then filled with compressed air to allow the liquid to be sprayed at high pressure.
As it is pumped by hand, the compressed air with which it is filled serves the primary purpose of allowing the liquid to be sprayed at high pressure - an important requirement for performance characteristics of the sprayer.
Flammable liquids must not be used with such equipment.
Read more on pressurized sprayers:
brainly.com/question/8842747
The power transferred by the motor is equal to the product between the current and the voltage:
However, the power used by the winch system is less than this value. In fact, the work done is equal to the weight of the load times the distance through which it has been lifted:
And the power used by the system is the work done divided by the time taken:
Therefore, the efficiency of the system is given by the ratio between the useful power and the power in input: